我将以下数据作为csv文件中时钟位置的管道中的方向提取,另存为D
[1] 1:48 3:10 11:00 8:36 9:30 9:16 12:08 4:14 1:04 9:06 1:12 11:22 9:44 1:14 1:42 10:22 11:26 2:18 2:44
[20] 9:22 1:00 12:58 10:14 10:02 10:02 10:24 1:04 1:28 2:22 1:56 9:42 10:06 10:16 2:28 10:18 10:38 10:00 9:52
[39] 10:30 9:26 1:26 5:32 2:02 11:08 8:42 8:52 12:50 1:02 1:30 7:08 7:04 7:10 7:08 10:18 10:10 9:20 8:40
[58] 9:10 9:06 8:16 8:28 6:14 10:08 10:10 1:04 1:44 5:58 6:48 5:52 9:30 10:30 10:12 10:34 10:06 2:38 4:32
[77] 6:20 1:28 2:30 2:06 9:38 2:42 9:22 10:44 1:38 11:44 1:46 9:00 11:10 11:10 11:14
78 Levels: 1:00 1:02 1:04 1:12 1:14 1:26 1:28 1:30 1:38 1:42 1:44 1:46 1:48 1:56 10:00 10:02 10:06 10:08 ... 9:52
尝试对数据进行一些练习:
> density(D)
density.default(D)出错:参数'x'必须是数字
> typeof(D)
[1] "integer"
> min(D)
Summary.factor中的错误(c(13L,49L,30L,63L,74L,70L,37L,50L,3L, :'min'对因素无意义
> strptime(D,format = %H-%M)
错误:“strptime(D,格式=%H - %”
中的意外特殊情况
我需要D作为有意义的时间格式值HH:MM进行分析和绘图。
答案 0 :(得分:3)
问题中显示的D
是一个因素,因此有必要先将其转换为更有意义的内容。
假设D
在最后的注释中可重复显示,将数据转换为chron times
类(显示为HH:MM:SS但在内部表示为一天的一小部分)所以例如1:00:00在内部表示为1/24并且绘图。 xaxt="n"
省略了X默认轴,以便我们可以使用axis
函数生成我们自己的自定义轴。
library(chron)
tt <- times(paste(D, "00", sep = ":"))
plot(density(tt), xaxt = "n")
axis(1, 0:24/24, 0:24) # show hours on X axis
可重现形式的输入D
假定为:
D <- structure(c(13L, 49L, 30L, 63L, 74L, 70L, 37L, 50L, 3L, 68L,
4L, 34L, 77L, 5L, 10L, 24L, 35L, 42L, 48L, 72L, 1L, 39L, 21L,
16L, 16L, 25L, 3L, 7L, 43L, 14L, 76L, 17L, 22L, 44L, 23L, 28L,
15L, 78L, 26L, 73L, 6L, 52L, 40L, 31L, 65L, 66L, 38L, 2L, 8L,
59L, 58L, 60L, 59L, 23L, 19L, 71L, 64L, 69L, 68L, 61L, 62L, 55L,
18L, 19L, 3L, 11L, 54L, 57L, 53L, 74L, 26L, 20L, 27L, 17L, 46L,
51L, 56L, 7L, 45L, 41L, 75L, 47L, 72L, 29L, 9L, 36L, 12L, 67L,
32L, 32L, 33L), .Label = c("1:00", "1:02", "1:04", "1:12", "1:14",
"1:26", "1:28", "1:30", "1:38", "1:42", "1:44", "1:46", "1:48",
"1:56", "10:00", "10:02", "10:06", "10:08", "10:10", "10:12",
"10:14", "10:16", "10:18", "10:22", "10:24", "10:30", "10:34",
"10:38", "10:44", "11:00", "11:08", "11:10", "11:14", "11:22",
"11:26", "11:44", "12:08", "12:50", "12:58", "2:02", "2:06",
"2:18", "2:22", "2:28", "2:30", "2:38", "2:42", "2:44", "3:10",
"4:14", "4:32", "5:32", "5:52", "5:58", "6:14", "6:20", "6:48",
"7:04", "7:08", "7:10", "8:16", "8:28", "8:36", "8:40", "8:42",
"8:52", "9:00", "9:06", "9:10", "9:16", "9:20", "9:22", "9:26",
"9:30", "9:38", "9:42", "9:44", "9:52"), class = "factor")
答案 1 :(得分:0)
使用G.Grothendieck构建的数据:
D <- structure(c(13L, 49L, 30L, 63L, 74L, 70L, 37L, 50L, 3L, 68L,
4L, 34L, 77L, 5L, 10L, 24L, 35L, 42L, 48L, 72L, 1L, 39L, 21L,
16L, 16L, 25L, 3L, 7L, 43L, 14L, 76L, 17L, 22L, 44L, 23L, 28L,
15L, 78L, 26L, 73L, 6L, 52L, 40L, 31L, 65L, 66L, 38L, 2L, 8L,
59L, 58L, 60L, 59L, 23L, 19L, 71L, 64L, 69L, 68L, 61L, 62L, 55L,
18L, 19L, 3L, 11L, 54L, 57L, 53L, 74L, 26L, 20L, 27L, 17L, 46L,
51L, 56L, 7L, 45L, 41L, 75L, 47L, 72L, 29L, 9L, 36L, 12L, 67L,
32L, 32L, 33L), .Label = c("1:00", "1:02", "1:04", "1:12", "1:14",
"1:26", "1:28", "1:30", "1:38", "1:42", "1:44", "1:46", "1:48",
"1:56", "10:00", "10:02", "10:06", "10:08", "10:10", "10:12",
"10:14", "10:16", "10:18", "10:22", "10:24", "10:30", "10:34",
"10:38", "10:44", "11:00", "11:08", "11:10", "11:14", "11:22",
"11:26", "11:44", "12:08", "12:50", "12:58", "2:02", "2:06",
"2:18", "2:22", "2:28", "2:30", "2:38", "2:42", "2:44", "3:10",
"4:14", "4:32", "5:32", "5:52", "5:58", "6:14", "6:20", "6:48",
"7:04", "7:08", "7:10", "8:16", "8:28", "8:36", "8:40", "8:42",
"8:52", "9:00", "9:06", "9:10", "9:16", "9:20", "9:22", "9:26",
"9:30", "9:38", "9:42", "9:44", "9:52"), class = "factor")
将因子转换为字符向量:
D_chr <- as.character(D)
然后:
D_time <- format(D_chr, format = "%H:%M:%S")
D_hms <- as.POSIXct(D_time, format = "%H:%M")
ClockTime <- data.frame(D_time,D_hms)
使用ggplot2
包,您可以这样制作密度图:
library(ggplot2)
ggplot(ClockTime) + theme_bw() +
geom_density(aes(D_hms,y=..scaled..)) +
scale_x_datetime(date_breaks="1 hours",date_labels ="%I %M") +
xlab("Hour")