Question

我有一个CSV文件，我希望文件中每个名字的第一个字母大写，其他名称是小写。我试图使用.title（）来完成这个。我希望使用大写字母（CleanNames.csv）的CSV文件将会拉动＆＃39;来自另一个CSV（ValidNames.csv）的这些名称是“拉动”的。来自无组织名称列表中的那些名称（10000DirtyNames.csv）。

这是我到目前为止所做的：

import re
import csv

with open("10000DirtyNames.csv", "r") as file:

    with open('ValidNames.csv', 'w+') as ValidNames_file:
        write = csv.writer(ValidNames_file, delimiter=',');
        data = file.read();
        pattern = "[A-Za-z]{1,}";
        search = re.findall(pattern, data);
        write.writerow(search);

        with open('CleanNames.csv', 'w') as CleanNames_file:
            write2 = csv.writer(CleanNames_file, delimiter=',');
            data2 = ValidNames_file.read();
            write2.writerow(data2.title());

除了CleanName.csv根本没有填充之外它可以工作。没有错误消息。我做错了什么？

Answer 1

我自己想出来，但我想我会发布我的解决方案，包括解决类似问题所需的人。

import re
import csv



with open("10000DirtyNames.csv", "r") as file:

    with open('ValidNames.csv', 'w+') as ValidNames_file:
        write = csv.writer(ValidNames_file, delimiter=',');
        data = file.read();
        pattern = "[A-Za-z]{1,}";
        search = re.findall(pattern, data);
        write.writerow(search);

        with open('ValidNames.csv') as ValidNames_file, open('CleanNames.csv', 'w') as CleanNames_file:
            for name in ValidNames_file:
                CleanNames_file.write(name.title())

在CSV文件上使用.title（）

1 个答案: