Question

我得到了以下名单＆＃34; phonenumbers＆＃34;。我很难删除包含＆＃39; \ n \ t \ t \ t \ t＆＃39;和＆＃39; \ n \ t \ t \ t \ t \ t＆＃39;。我试过＆＃34;尝试除了＆＃34; -methode并删除（＆＃39; \ n \ t \ t \ t \ t \ t \ t＆＃39;）但无法使其正常工作。有什么提示吗？

[＆＃39;（02271）6 79＆＃39;，＆＃39; 70＆＃39;，＆＃39; \ n \ t \ t \ t \ t＆＃39;，＆＃39;（02271）6 79＆＃39;，＆＃39; \ n \ t \ t \ t \ t \ t＆＃39 ;，＆＃39; 70＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39;（02181）27 0＆＃39;，＆＃39; \ n \ t \ t \ t \ t＆＃39;，＆＃39; 3-0＆＃39;，＆＃39; \ n \ t \ t \ t \ t＆t 39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39;（02181）27 0＆＃39;，＆＃39; \ n \ t \ t \ t \ t＆t 39;，＆＃39; 3-0＆＃ 39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t \ t＆＃39;，＆＃39;（02161）24 19＆＃39;，＆＃ 39; \ n \ t \ t \ t \ t \ t，＆＃39;，＆＃39; 40＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t \ t＆＃39;，＆＃39;（02161）24 19＆＃39;，＆＃39; \ n \ t \ t \ t \ t \ t \ t＆＃39;，＆＃39; 40＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39;（02131）66 67＆＃39;，＆＃39; \ n \ t \ t \ t \ t \ t \ t＆＃39;，＆＃39; 10＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39;（02131）66 67＆＃39;，＆＃39; \ n \ t \ t \ t \ t \ t \ t＆＃39;，＆＃39; 10＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39;（02103）39 00＆＃39;，＆＃39; \ n \ t \ t \ t \ t \ t \ t＆＃39;，＆＃39; 93＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t \ t＆＃39;，＆＃39;（02103）39 00＆＃39;，＆＃39; \ n \ t \ t \ t \ t \ t \ t＆＃39;，＆＃39; 93＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t \ t \ t＆＃39;，＆＃39;（02173）2 04 7＆＃39; ，＆＃39; \ n \ t \ t \ t \ t＆＃39;，＆＃39; 3-0＆＃39;，＆＃39; \ n \ t \ t \ t \ t＆t 39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39;（02173）2 04 7＆＃39;，＆＃39; \ n \ t \ t \ t \ t \ tt＆＃39;，＆＃39; 3- 0＆＃39;，＆＃39; \ n \ t \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39;（02235）9 23 04＆＃39; ，＆＃39; \ n \ t \ t \ t \ t \ t，＆＃39;，＆＃39; 30＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t＆t 39，＆＃39;（02235）9 23 04＆＃39; ，＆＃39; \ n \ t \ t \ t \ t \ t，＆＃39;，＆＃39; 30＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t \ t \ t＆＃39;，＆＃39;（0221）3 46 79 40＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t \ t＆＃39 ;，＆＃39; \ n \ t \ t \ t \ tt＆＃39;，＆＃39;（0221）3 46 79 40＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39; ，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39;（02232）4 23＆＃39;，＆＃39; \ n \ t \ t \ t \ t \ t＆t 39;，＆＃ 39; 05＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t \ t＆＃39;，＆＃39;（02232）4 23＆＃39;，＆＃39; \ n \ t \ t \ t \ t \ t \ t＆＃39;，＆＃39; 05＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t＆t 39，＆＃39;（0157）86 85 74＆＃39; ，＆＃39; \ n \ t \ t \ t \ t \ t，＆＃39;，＆＃39; 43＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t \ t＆t 39，＆＃39;（0157）86 85 74＆＃39; ，＆＃39; \ n \ t \ t \ t \ t \ t，＆＃39;，＆＃39; 43＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t \ t＆＃39;，＆＃39;（02181）2 78 11＆＃39; ，＆＃39; \ n \ t \ t \ t \ t \ t，＆＃39;，＆＃39; 47＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t＆t 39，＆＃39;（02181）2 78 11＆＃39; ，＆＃39; \ n \ t \ t \ t \ t \ t，＆＃39;，＆＃39; 47＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39;（02181）47 49 0＆＃39; ，＆＃39; \ n \ t \ t \ t \ t＆＃39;，＆＃39; 0-0＆＃39;，＆＃39; \ n \ t \ t \ t \ t＆t 39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39;（02181）47 49 0＆＃39;，＆＃39; \ n \ t \ t \ t \ t \ tt＆＃39;，＆＃39; 0- 0＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39;（02202）1 88＆＃39;，＆＃39; \ n \ t \ t \ t \ t \ t \ t＆＃39;，＆＃39; 60＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t \ t＆＃39;，＆＃39;（02202）1 88＆＃39;，＆＃39; \ n \ t \ t \ t \ t \ t \ t＆＃39;，＆＃39; 60＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39;（0211）23 80＆＃39;，＆＃39; \ n \ t \ t \ t \ t \ t \ t＆＃39;，＆＃39; 70＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39;（0211）23 80＆＃39;，＆＃39; \ n \ t \ t \ t \ t \ t \ t＆＃39;，＆＃39; 70＆＃39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39; \ n \ t \ t \ t \ t＆t 39，＆＃39;（02235）9 23 0＆＃39; ，＆＃39; \ n \ t \ t \ t \ t＆＃39;，＆＃39; 4-0＆＃39;，＆＃39; \ n \ t \ t \ t \ t＆t 39;，＆＃39; \ n \ t \ t \ t＆＃39;，＆＃39;（02235）9 23 0＆＃39;，＆＃39; \ n \ t \ t \ t \ t \ tt＆＃39;，＆＃39; 4- 0＆＃39;，＆＃39; \ n \ t \ t \ t \ tt＆＃39;]

Answer 1

你可以选择像

这样的简单表达式

from itertools import product

def brute_force():
    for length in range(min_length, max_length + 1):
        for p in product(chars, repeat=length):
            guess = ''.join(p)
            if guess == password:
                return guess

在^\s+$：

Python

这会产生并剥离所有不仅从开始到结束的空格的数字：

import re

lst = ['(02271) 6 79', ' 70', '\n\t\t\t', '(02271) 6 79', '\n\t\t\t\t', ' 70', '\n\t\t\t', '\n\t\t\t', '(02181) 27 0', '\n\t\t\t\t', '3-0', '\n\t\t\t', '\n\t\t\t', '(02181) 27 0', '\n\t\t\t\t', '3-0', '\n\t\t\t', '\n\t\t\t', '(02161) 24 19', '\n\t\t\t\t', ' 40', '\n\t\t\t', '\n\t\t\t', '(02161) 24 19', '\n\t\t\t\t', ' 40', '\n\t\t\t', '\n\t\t\t', '(02131) 66 67', '\n\t\t\t\t', ' 10', '\n\t\t\t', '\n\t\t\t', '(02131) 66 67', '\n\t\t\t\t', ' 10', '\n\t\t\t', '\n\t\t\t', '(02103) 39 00', '\n\t\t\t\t', ' 93', '\n\t\t\t', '\n\t\t\t', '(02103) 39 00', '\n\t\t\t\t', ' 93', '\n\t\t\t', '\n\t\t\t', '(02173) 2 04 7', '\n\t\t\t\t', '3-0', '\n\t\t\t', '\n\t\t\t', '(02173) 2 04 7', '\n\t\t\t\t', '3-0', '\n\t\t\t', '\n\t\t\t', '(02235) 9 23 04', '\n\t\t\t\t', ' 30', '\n\t\t\t', '\n\t\t\t', '(02235) 9 23 04', '\n\t\t\t\t', ' 30', '\n\t\t\t', '\n\t\t\t', '\n\t\t\t\t', '(0221) 3 46 79 40', '\n\t\t\t', '\n\t\t\t', '\n\t\t\t\t', '(0221) 3 46 79 40', '\n\t\t\t', '\n\t\t\t', '(02232) 4 23', '\n\t\t\t\t', ' 05', '\n\t\t\t', '\n\t\t\t', '(02232) 4 23', '\n\t\t\t\t', ' 05', '\n\t\t\t', '\n\t\t\t', '(0157) 86 85 74', '\n\t\t\t\t', ' 43', '\n\t\t\t', '\n\t\t\t', '(0157) 86 85 74', '\n\t\t\t\t', ' 43', '\n\t\t\t', '\n\t\t\t', '(02181) 2 78 11', '\n\t\t\t\t', ' 47', '\n\t\t\t', '\n\t\t\t', '(02181) 2 78 11', '\n\t\t\t\t', ' 47', '\n\t\t\t', '\n\t\t\t', '(02181) 47 49 0', '\n\t\t\t\t', '0-0', '\n\t\t\t', '\n\t\t\t', '(02181) 47 49 0', '\n\t\t\t\t', '0-0', '\n\t\t\t', '\n\t\t\t', '(02202) 1 88', '\n\t\t\t\t', ' 60', '\n\t\t\t', '\n\t\t\t', '(02202) 1 88', '\n\t\t\t\t', ' 60', '\n\t\t\t', '\n\t\t\t', '(0211) 23 80', '\n\t\t\t\t', ' 70', '\n\t\t\t', '\n\t\t\t', '(0211) 23 80', '\n\t\t\t\t', ' 70', '\n\t\t\t', '\n\t\t\t', '(02235) 9 23 0', '\n\t\t\t\t', '4-0', '\n\t\t\t', '\n\t\t\t', '(02235) 9 23 0', '\n\t\t\t\t', '4-0', '\n\t\t\t']

rx = re.compile(r'^\s+$')

lst = [item.strip() for item in lst if not rx.match(item)]
print(lst)

<小时/> 正如@dawg指出的那样，实际上并不需要正则表达式：

['(02271) 6 79', '70', '(02271) 6 79', '70', '(02181) 27 0', '3-0', '(02181) 27 0', '3-0', '(02161) 24 19', '40', '(02161) 24 19', '40', '(02131) 66 67', '10', '(02131) 66 67', '10', '(02103) 39 00', '93', '(02103) 39 00', '93', '(02173) 2 04 7', '3-0', '(02173) 2 04 7', '3-0', '(02235) 9 23 04', '30', '(02235) 9 23 04', '30', '(0221) 3 46 79 40', '(0221) 3 46 79 40', '(02232) 4 23', '05', '(02232) 4 23', '05', '(0157) 86 85 74', '43', '(0157) 86 85 74', '43', '(02181) 2 78 11', '47', '(02181) 2 78 11', '47', '(02181) 47 49 0', '0-0', '(02181) 47 49 0', '0-0', '(02202) 1 88', '60', '(02202) 1 88', '60', '(0211) 23 80', '70', '(0211) 23 80', '70', '(02235) 9 23 0', '4-0', '(02235) 9 23 0', '4-0']

Answer 2

试试这个，

result = [i for i in lst if not i.endswith('\t\t')]

Answer 3

您可以使用list-comprehension创建strings列表，其中每个人都必须通过all中c个字符string的测试1}}是in：'\t\n'。我认为这是最有效的，通用的解决方案，适用于只包含strings和tabs的{{1}}，在Python中也非常易读：

newlines

给出正确的结果：

[i for i in lst if all(c not in '\t\n' for c in i)]

你也可以使用str.isspace()这个更短，但可能（我不确定['(02271) 6 79', ' 70', '(02271) 6 79', ' 70', '(02181) 27 0', '3-0', '(02181) 27 0', '3-0', '(02161) 24 19', ' 40', '(02161) 24 19', ' 40', '(02131) 66 67', ' 10', '(02131) 66 67', ' 10', '(02103) 39 00', ' 93', '(02103) 39 00', ' 93', '(02173) 2 04 7', '3-0', '(02173) 2 04 7', '3-0', '(02235) 9 23 04', ' 30', '(02235) 9 23 04', ' 30', '(0221) 3 46 79 40', '(0221) 3 46 79 40', '(02232) 4 23', ' 05', '(02232) 4 23', ' 05', '(0157) 86 85 74', ' 43', '(0157) 86 85 74', ' 43', '(02181) 2 78 11', ' 47', '(02181) 2 78 11', ' 47', '(02181) 47 49 0', '0-0', '(02181) 47 49 0', '0-0', '(02202) 1 88', ' 60', '(02202) 1 88', ' 60', '(0211) 23 80', ' 70', '(0211) 23 80', ' 70', '(02235) 9 23 0', '4-0', '(02235) 9 23 0', '4-0']确定）稍微慢，因为它会检查 all < / em> 100%字符：

whitespace

给出相同的结果。

从列表

3 个答案: