Question

当我将属性歌词设置为lyrics_bday时，代码正常工作，在lyric_bulls或lyrics_tamasha的情况下，它会给出NameError。为什么会这样？

class Song(object):
def __init__(self, lyrics):
    #self.lyrics is the instance while lyrics is the attribute
    self.lyrics =  lyrics_bday

def sing_me_a_song(self):
    for line in self.lyrics:
        print line

lyrics_bday = ["\n Happy Birthday to you", "\n I dont want to get sued", "\n So I'll stop here"]
happy_bday = Song(lyrics_bday) #passing the variable to class

lyrics_bulls = ["\n They rally around the family", "\n With pockets full of shells"]
bulls_on_parade = Song(lyrics_bulls)

lyrics_tamasha = ["\n Pal bhar sambhal jao", "\ndil ko kaise samjhaun", "\nAgar tum sath ho"]
agar_tum_sath_ho = Song(lyrics_tamasha)

happy_bday.sing_me_a_song()

bulls_on_parade.sing_me_a_song()

Answer 1

不确定您要在const groupByArray = (array1, array2) => { const array2Set = new Set(array2); return array1.reduce((r, s) => { if(!r[r.length - 1] || array2Set.has(s)) { r.push([]); } r[r.length - 1].push(s); return r; }, []) }; const array1 = ["str1", "str2", "str3", "str4", "str5", "str6"]; console.log(groupByArray(array1, ["str2","str5"])); console.log(groupByArray(array1, ["str2","str3"]));中做什么，但截至目前，您的代码仅包含为歌词分配值; 在__init__，您要将__init__分配给lyrics_bday，并且您将参数设为self.lyrics，因此您需要使用lyrics 但是如果你正在调用函数那么为什么不在其中传递参数呢？见下面的代码示例：

self.lyrics = lyrics

输出：

class Song(object):
    def __init__(self, **kwargs):
        # ... include your desire code here
        self.default_lyrics = ["*-"*10,"DEMO","lyrics..........","*-"*10]

    def sing_me_a_song(self, lyrics=None):
        if not lyrics:
            lyrics = self.default_lyrics
        for line in lyrics:
            print(line)

song_object = Song()
lyrics_bday = ["\n Happy Birthday to you", "\n I dont want to get sued", "\n So I'll stop here"]
lyrics_bulls = ["\n They rally around the family", "\n With pockets full of shells"]
lyrics_tamasha = ["\n Pal bhar sambhal jao", "\ndil ko kaise samjhaun", "\nAgar tum sath ho"]

song_object.sing_me_a_song(lyrics_bday)
song_object.sing_me_a_song(lyrics_bulls)
song_object.sing_me_a_song()

你可以看到你不需要每次都创建类对象;只需在必要时传递参数，并考虑Happy Birthday to you I dont want to get sued So I'll stop here They rally around the family With pockets full of shells *-*-*-*-*-*-*-*-*-*- DEMO lyrics.......... *-*-*-*-*-*-*-*-*-*-如果没有歌词传递给函数，你可以使用预定义的歌词值进行打印。

NameError中的歧义：

1 个答案: