大于计划

Question

我试图编写一个程序，当给出两个数字时，它会告诉你女巫更大或是否相等。当我运行下面的代码时，它不适用于任何大于10的数字

print "Please give me your first number."
first_number = gets.chomp 


print "Please give me your second number."
second_number = gets.chomp 

if first_number == second_number
    print "These two are equal."
elsif first_number > second_number
    print "Your first number is greater." 
elsif first_number < second_number
    print "Your second number is greater."
end 

Answer 1

由于gets.comp的结果是字符串，>和<按字母顺序比较字典中的输入。以下是按字母顺序排序的字符串列表：

"1"
"10"
"1300930184"
"2"
"2139182"
"23"
"3"
"aardvark"
"ab"
"avalanche"
"caramel"

您想要的是将字符串转换为整数（整数），然后比较它们。这可以通过例如完成。通过将调用包装成chomp：first_number = Integer(gets.chomp)

Answer 2

试试这个。

print "Please give me your first number."
first_number = gets.to_i 

print "Please give me your second number."
second_number = gets.to_i 

puts case first_number <=> second_number
     when -1
       "Your second number is greater."
     when 0
       "These two are equal."
     when 1
       "Your first number is greater."
     end

正如其他人所提到的，gets返回一个字符串，因此对于比较，您必须将字符串转换为整数。另请参阅Integer#<=>。

Answer 3

解析输入后（如上文其他答案所述）我建议采用这种报告方法，更准确地解决问题，并避免需要进行明确的比较：

if first_number == second_number
  puts "The numbers are equal."
else
  higher_number = [first_number, second_number].max
  puts "#{higher_number} is the higher number."
end

（虽然我承认，在这个问题的层面上获得阵列的最大值可能是一个触手可及。）