Question

我正在EDX平台上进行自学课程CS50，目标是询问用户信用卡号，然后验证它是否是有效的美国运通卡，万事达卡或维萨卡。

我试图分裂一个大于10的数字（格式化为字符串），以便结果例如＆＃34; 14＆＃34; =＆＃34; 1＆＃34;和＆＃34; 4＆＃34;我们的想法是两个数字都会附加到列表[]。

我正在尝试根据Hans Peter Luhn发明的算法实施信用卡校验和检查，我被困在算法的第二部分（写作对代码的评论），因为算法指定我必须将14分成1 4然后做总和。

测试用信用卡：378282246310005 到目前为止我有这个结果：14 + 4 + 4 + 8 + 6 + 0 + 0 = 36 //差我需要继续做的是：1 + 4 + 4 + 4 + 8 + 6 + 0 + 0 = 27 //好

这是我的代码：

def main():
    cCNumber = str(input("Ingrese el numero de la tarjeta de credito: "))
    if cCNumber[0] == "3" and (cCNumber[1] == "4" or cCNumber[1] == "7") :
            numbers = listInts(cCNumber)
            listSumador = checkSum(numbers)
            listSumadorStr = str(listSumador)
            print(listSumadorStr)
            print("Amex")

#Convert string to a list of Ints.
def listInts(stRnumber):
    listNumbers = []
    for i in range(0,len(stRnumber),1):
        listNumbers.append(int(stRnumber[i]))
    return listNumbers

#Implement the following algorithm:
    #1: Multiply every other digit by 2, starting with the number’s second-to-last digit, and then add those products' digits together.
    #2: Add the sum to the sum of the digits that weren’t multiplied by 2.
    #3: if the total’s last digit is 0 (or, put more formally, if the total modulo 10 is congruent to 0), the number is valid!
def checkSum(numbers):
    sumador = []
    for i in range(1,len(numbers),2):
        provisoryList = []
        provisoryList.append(int(numbers[i]) * 2)
        sumador.append(int(numbers[i]) * 2) 
    return sumador

if __name__ == "__main__":
    main()

拆分char或int :: Python 3

0 个答案: