Question

如何在IHttpActionResult操作，Web API控制器中实现以下功能？

我是否需要将HttpResponseBase修改为其他内容？

public void ZipFilesToResponse(HttpResponseBase response, IEnumerable<Asset> files, string zipFileName)
{
    using (var zipOutputStream = new ZipOutputStream(response.OutputStream))
    {
        zipOutputStream.SetLevel(0); // 0 - store only to 9 - means best compression
        response.BufferOutput = false;
        response.AddHeader("Content-Disposition", "attachment; filename=" + zipFileName);
        response.ContentType = "application/octet-stream";

        foreach (var file in files)
        {
            var entry = new ZipEntry(file.FilenameSlug())
            {
                DateTime = DateTime.Now,
                Size = file.Filesize
            };
            zipOutputStream.PutNextEntry(entry);
            storageService.ReadToStream(file, zipOutputStream);
            response.Flush();
            if (!response.IsClientConnected)
            {
               break;
            }
        }
        zipOutputStream.Finish();
        zipOutputStream.Close();
    }
    response.End();
}

在这里使用：

[HttpPost]
[Route("DownloadFiles/{company_id}")]
public IHttpActionResult DownloadFiles(Int64 company_id, TasksFilterModel searchModel)
{
     var files = .....;
     ZipFilesToResponse(_______,files,"download.zip");
     return ????
}

Answer 1

您当前的public class MyController : Controller { [HttpPost] [Route("DownloadFiles/{company_id}")] public void DownloadFiles(Int64 company_id, TasksFilterModel searchModel) { var files = ...; ZipFilesToResponse(HttpContext.Response, files, "download.zip"); } }方法更适用于常规MVC，而不是Web API。一种选择是简单地将此操作移动到MVC控制器而不是Web API控制器。

ZipFilesToResponse

由于ZipFilesToResponse方法直接写入HttpContext.Response对象，因此无需返回任何内容。

或者，如果您想坚持使用纯粹的Web API，我们可以修改HttpResponseMessage方法来创建[Route("DownloadFiles")] [HttpGet] public HttpResponseMessage DownloadFiles() { var files = ...; return ZipContentResult(files, "download.zip"); } protected HttpResponseMessage ZipContentResult(IEnumerable<Asset> files, string zipFileName) { var pushStreamContent = new PushStreamContent((stream, content, context) => { using (var zipOutputStream = new ZipOutputStream(stream)) { zipOutputStream.SetLevel(0); // 0 - store only to 9 - means best compression foreach (var file in files) { var entry = new ZipEntry(file.FilenameSlug()) { DateTime = DateTime.Now, Size = file.Filesize }; zipOutputStream.PutNextEntry(entry); storageService.ReadToStream(file, zipOutputStream); stream.Flush(); } zipOutputStream.Finish(); zipOutputStream.Close(); } stream.Close(); }, "application/zip"); pushStreamContent.Headers.Add("Content-Disposition", "attachment; filename=" + zipFileName); return new HttpResponseMessage(HttpStatusCode.OK) { Content = pushStreamContent }; }，然后从您的操作中返回。

{{1}}

将HttpResponseBase转换为IHttpActionResult

1 个答案: