Fragler里面的RecyclerView我的代码没有错误

时间:2017-12-22 11:27:59

标签: android-recyclerview android-volley android-fragmentactivity recycler-adapter

我是android studio的初学者,

我在Fragment中使用RecyclerView时遇到了一些问题。我无法在我的代码中找到错误。当我运行我的应用程序时它会运行但是每当我打开特定的片段时它都会显示click me for screen shot

添加我的代码如下

ListFragment.java

 public class ListFragment extends Fragment {
//this is the JSON Data URL
//make sure you are using the correct ip else it will not work
final String URL_PRODUCTS = "http://192.168.0.12/Api.php";

//a list to store all the products
List<Person> personList;

//the recyclerview
RecyclerView recyclerView;

@Override
public void onCreate(@Nullable Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    Toast.makeText(MainActivity.appContext, "Created", Toast.LENGTH_SHORT).show();
}

public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
    View rootView = inflater.inflate(R.layout.fragment_list, container, false);

    Toast.makeText(MainActivity.appContext, "Created in View", Toast.LENGTH_SHORT).show();
    //getting the recyclerview from xml
    recyclerView = (RecyclerView) rootView.findViewById(R.id.recylcerView);



    //initializing the productlist
    personList = new ArrayList<>();

    //this method will fetch and parse json
    //to display it in recyclerview
    loadProducts();
    return rootView;

}

private void loadProducts() {

    /*
    * Creating a String Request
    * The request type is GET defined by first parameter
    * The URL is defined in the second parameter
    * Then we have a Response Listener and a Error Listener
    * In response listener we will get the JSON response as a String
    * */
    StringRequest stringRequest = new StringRequest(Request.Method.POST, URL_PRODUCTS,
            new Response.Listener<String>() {
                @Override
                public void onResponse(String response) {
                    try {
                        //converting the string to json array object
                        JSONArray array = new JSONArray(response);

                        //traversing through all the object
                        for (int i = 0; i < array.length(); i++) {

                            //getting product object from json array
                            JSONObject product = array.getJSONObject(i);

                            //adding the product to product list
                            personList.add(new Person(
                                    product.getInt("id"),
                                    product.getString("title"),
                                    product.getString("shortdesc"),
                                    product.getDouble("rating"),
                                    product.getDouble("price"),
                                    product.getString("image")
                            ));
                        }

                        //creating adapter object and setting it to recyclerview
                        PersonsAdapter adapter = new PersonsAdapter(MainActivity.appContext, personList);
                        recyclerView.setAdapter(adapter);
                        recyclerView.setLayoutManager(new LinearLayoutManager(MainActivity.appContext));
                    } catch (JSONException e) {
                        e.printStackTrace();
                    }
                }
            },
            new Response.ErrorListener() {
                @Override
                public void onErrorResponse(VolleyError error) {

                }
            });

    //adding our stringrequest to queue

    Volley.newRequestQueue(MainActivity.appContext).add(stringRequest);


}


}

以下用于打开片段的代码

fragmentManager.beginTransaction().replace(R.id.frame_container, new ListFragment(), "ListFragment").commit();

1 个答案:

答案 0 :(得分:1)

更改守则

fragmentManager.beginTransaction().replace(R.id.frame_container, new MyListFragment(), "MyListFragment").commit();

第二个参数应该是碎片。

第3个参数是用于识别碎片的TAG。

第一个参数是活动中FragmeLayout或容器,其中片段将被夸大。

你不能使用名称列表片段,因为Itz是Android本身的默认片段。有时当您调用 ListFragment 时,可能会调用该函数