Question

假设我有2个可以互相呼叫的功能

 public static function goToAction($action,$sender_id)
{
    $actions = array();
    $logic = file_get_contents('../../logic/logic.json');
    $logic_array = json_decode($logic, true);
    unset($logic);
    if (!isset($logic_array[$action])) {
        return false;
    } else {
        foreach ($logic_array[$action] as $action) {
            $actions[] = self::parseActionType($action,$sender_id);
        }
    }
    return $actions;
}


 public static function parseActionType($actions,$sender_id)
{
    $data = array();
    foreach ($actions as $key => $action) {
        switch ($key) {
            case 'goto': { 
                      $goto_actions = self::goToAction($action,$sender_id);
                      foreach ($goto_actions as $goto_action){
                      $data[] = $goto_action;
                  } break;
                  ...
   }
}
return $data;
}

这是我的json文件：

 "no_return": [
{ "text": "Должно быть: 1, 2, 3"},
{ "text": "1" },
{ "goto": "2nr", "no_return": true},
{ "text": "5" }
],
"2nr": [
{ "text": "2" },
{ "goto": "3", "no_return": true},
{ "text": "4"}
],
"3nr": [
{ "text": "3" }
],

它返回12345，它是正确的，但是如果将no_return设置为true，如何才能返回123？也许函数必须返回一些东西？

Answer 1

proto_library(
name = "GreeterServices_proto",
srcs = ["GreeterServices.proto"],
deps = [
    "@googleapi//:annotations_proto",
])

使用循环内部的break会停止它，即使剩下更多的元素，还有继续这将结束当前运行并继续下一个元素。

PHP停止2个相互调用的函数

1 个答案: