Question

我有一个JSON数据，它保存在一个文件中，看起来像这样。

{"@odata.context":"/redfish/v1/$metadata#ServiceRoot(Oem,Id,Name,RedfishVersion,UUID,Links,Systems,Chassis,Managers,Tasks,SessionService,AccountService,EventService,Registries,JsonSchemas)","@odata.id":"/redfish/v1/","@odata.type":"#ServiceRoot.v1_0_5.ServiceRoot","Oem":{"ts_fujitsu":{"@odata.type":"http://ts.fujitsu.com/redfish-schemas/v1/FTSSchema.v1_0_0#FTSServiceRoot.v1_0_0.FTSServiceRoot","FileDownload":{"@odata.id":"/redfish/v1/Oem/ts_fujitsu/FileDownload"},"CASConfiguration":{"Enabled":false,"DisplayLoginPage":false,"ServerLoginUrl":null,"ServerLogoutUrl":null}}},"Id":"RootService","Name":"Root Service","RedfishVersion":"1.0.5","UUID":"74fce745-28ad-410a-bbf8-9291d486b457","Links":{"Oem":{},"Sessions":{"@odata.id":"/redfish/v1/SessionService/Sessions"}},"Systems":{"@odata.id":"/redfish/v1/Systems"},"Chassis":{"@odata.id":"/redfish/v1/Chassis"},"Managers":{"@odata.id":"/redfish/v1/Managers"},"Tasks":{"@odata.id":"/redfish/v1/TaskService"},"SessionService":{"@odata.id":"/redfish/v1/SessionService"},"AccountService":{"@odata.id":"/redfish/v1/AccountService"},"EventService":{"@odata.id":"/redfish/v1/EventService"},"Registries":{"@odata.id":"/redfish/v1/Registries"},"JsonSchemas":{"@odata.id":"/redfish/v1/JsonSchemas"},"@Redfish.Copyright":"Copyright 2014-2017 Distributed Management Task Force, Inc. (DMTF). For the full DMTF copyright policy, see http://www.dmtf.org/about/policies/copyright.","@odata.etag":"1511366122"}

现在我使用Java在JSONBject中保存这些数据。我需要解析这些数据并将其保存到MongoDB。我从URL获取此数据。检索数据并将其保存到文件的代码如下。

public JsonObject authen() {
    JsonObject myRestData = new JsonObject();
    try{
          URL myUrl = new URL("http://{physical-system}/redfish/v1");
          URLConnection urlCon = myUrl.openConnection();
          urlCon.setRequestProperty("Method", "GET");
          urlCon.setRequestProperty("Accept", "application/json");
          urlCon.setConnectTimeout(5000);
          //set the basic auth of the hashed value of the user to connect
          urlCon.addRequestProperty("Authorization", GetMyCredentials() );
          InputStream is = urlCon.getInputStream();
          InputStreamReader isR = new InputStreamReader(is);
          BufferedReader reader = new BufferedReader(isR);
          StringBuffer buffer = new StringBuffer();
          String line = "";
          while( (line = reader.readLine()) != null ){
            buffer.append(line);
          }
          reader.close();
          JsonParser parser = new JsonParser();
          myRestData = (JsonObject) parser.parse(buffer.toString());

          return myRestData;

        }catch( MalformedURLException e ){
          e.printStackTrace();
          myRestData.addProperty("error", e.toString());
          return myRestData;
        }catch( IOException e ){
          e.printStackTrace();
          myRestData.addProperty("error", e.toString());
          return myRestData;
        }
}

public void writer(JsonObject o) throws JSONException, IOException {
    try (FileWriter file = new FileWriter("file1.json")) {
        file.write(o.toString());
        System.out.println("Successfully Copied JSON Object to File...");
        System.out.println("\nJSON Object: " + o);
    }
public void parser(JsonObject o) throws JSONException {
    JsonElement n = o.get("UUID");
    System.out.println(n);

现在，我想在mongoDB中保存这个JSON数据。我想通过解析然后保存它来保存它。但我的数据太多无法解析。我想将所有数据保存到MongoDB。如果我想从数据库中得到任何东西，我可以轻松地查询它。我正在考虑一种聪明的方法来做到这一点。 [我是MongoDB的新手＆amp; JSON]

Answer 1

您应该使用mongo-java-driver的最新版本，只需编写

即可

MongoClient client = new MongoClient("<your connection string (optional)>");
MongoCollection<Document> collection = client.getDatabase("<Database>").getCollection("<Collection>");
Document doc = Document.parse(<Your JSON string>);
collection.insertOne(doc);

您的JSON字符串为buffer.toString()

Answer 2

您可以使用save的{{1}}方法将JSON直接保存到MongoDB中。

这是一个列表示例：

DBCollection

解析JSON数据并将其保存到MongoDB

2 个答案: