我是c ++和cython的新手,并且对在Cython中包装C ++朋友非成员运算符感到困惑。这是我试图包装的一个小例子,但失败了。非常感谢
现在,我如何在pyx文件中声明友元运算符
all files can be found here, makefile for test -
Rectangle.h
namespace shapes {
class Rectangle {
public:
int x0, y0, x1, y1;
Rectangle(int x0=0, int y0=0, int x1=0, int y1=0);
~Rectangle();
int getLength();
Rectangle operator+(const Rectangle& target);
friend Rectangle operator-(const Rectangle & left, const Rectangle & right);
};
}
Rectangle.cpp
#include "Rectangle.h"
using namespace shapes;
Rectangle::Rectangle(int X0, int Y0, int X1, int Y1) {
x0 = X0;
y0 = Y0;
x1 = X1;
y1 = Y1;
}
int Rectangle::getLength() {
return (x1 - x0);
}
Rectangle::~Rectangle()
{
}
Rectangle Rectangle::operator+(const Rectangle & target) {
return Rectangle(x0+target.x0, y0+target.y0,x1+target.x1,y1+target.y1);
}
Rectangle operator-(const Rectangle & left,const Rectangle & right) {
return Rectangle(left.x0 - right.x0,
left.y0-right.y0,
left.x1-right.x1,
left.y1-right.y1);
}
pyx文件
from libcpp.vector cimport vector
from cython.operator cimport dereference as deref
# c++ interface to cython
cdef extern from "Rectangle.h" namespace "shapes":
cdef cppclass Rectangle:
Rectangle() except +
Rectangle(int, int, int, int) except +
int x0, y0, x1, y1
int getLength()
Rectangle opadd "operator+"(Rectangle right)
Rectangle opsub "operator-" (Rectangle right)
# Rectangle opsub "operator-"(Rectangle left ,Rectangle right)
# cdef extern from "Rectangle.h" namespace "shapes":
# cdef Rectangle opsub "operator-"(Rectangle left ,Rectangle right)
# creating a cython wrapper class
cdef class PyRectangle:
cdef Rectangle *thisptr # hold a C++ instance which we're wrapping
def __cinit__(self, int x0=0, int y0=0, int x1=0, int y1=0):
self.thisptr = new Rectangle(x0, y0, x1, y1)
def __dealloc__(self):
del self.thisptr
def getLength(self):
return self.thisptr.getLength()
def __add__(PyRectangle left,PyRectangle right):
cdef Rectangle rect = left.thisptr.opadd(right.thisptr[0])
cdef PyRectangle sum = PyRectangle(rect.x0,rect.y0,rect.x1,rect.y1)
return sum
def __sub__(PyRectangle left,PyRectangle right):
cdef Rectangle rect = left.thisptr.opsub(right.thisptr[0])
# cdef Rectangle rect = opsub(left.thisptr[0],right.thisptr[0])
cdef PyRectangle sub = PyRectangle(rect.x0,rect.y0,rect.x1,rect.y1)
return sub
def __repr__(self):
return "PyRectangle[%s,%s,%s,%s]" % (
self.thisptr.x0,
self.thisptr.y0,
self.thisptr.x1,
self.thisptr.y1)
我尝试了serval方法,例如
cdef extern from "Rectangle.h" namespace "shapes":
cdef Rectangle opsub "operator-"(Rectangle left ,Rectangle right)
或者只是假装它是cppclass声明中的成员定义的运算符
Rectangle opsub "operator-" (Rectangle right)
我无法编译两种方式,因为它显示了
error: no member named 'operator-' in 'shapes::Rectangle'
答案 0 :(得分:2)
抱歉,我在Rectangle.cpp中发现了一个很大的错误。运算符的定义需要以命名空间
作为前缀 Rectangle shapes::operator-(const Rectangle & left,const Rectangle & right) {
return Rectangle(left.x0 - right.x0,
left.y0-right.y0,
left.x1-right.x1,
left.y1-right.y1);
}
根据DavidW的提示,可以修改rect.pyx以直接调用操作符。
# c++ interface to cython
cdef extern from "Rectangle.h" namespace "shapes":
cdef cppclass Rectangle:
Rectangle() except +
Rectangle(int, int, int, int) except +
int x0, y0, x1, y1
int getLength()
Rectangle operator+(Rectangle right)
Rectangle operator-(Rectangle right)
#### nonmember operator can also work :
# cdef extern from "Rectangle.h" namespace "shapes":
# cdef Rectangle operator-(Rectangle left ,Rectangle right)
# creating a cython wrapper class
cdef class PyRectangle:
cdef Rectangle *thisptr # hold a C++ instance which we're wrapping
def __cinit__(self, int x0=0, int y0=0, int x1=0, int y1=0):
self.thisptr = new Rectangle(x0, y0, x1, y1)
def __dealloc__(self):
del self.thisptr
def getLength(self):
return self.thisptr.getLength()
def __add__(PyRectangle left,PyRectangle right):
cdef Rectangle rect = left.thisptr[0] + right.thisptr[0]
cdef PyRectangle sum = PyRectangle(rect.x0,rect.y0,rect.x1,rect.y1)
return sum
def __sub__(PyRectangle left,PyRectangle right):
cdef Rectangle rect = left.thisptr[0] - right.thisptr[0]
# cdef Rectangle rect = opsub(left.thisptr[0],right.thisptr[0])
cdef PyRectangle sub = PyRectangle(rect.x0,rect.y0,rect.x1,rect.y1)
return sub