将uint8数组转换为cv2可读图像

Question

我有一大堆50K图像保存为3 * 1024阵列（RGB 32X32），我想将它们转换为cv2格式。

# Here I read the images
def unpickle(file):
    import cPickle
    with open(file, 'rb') as fo:
        dict = cPickle.load(fo)
    return dict


def my_main():
    print 'unpicking training set images'
    d = unpickle(pickled_training_files)
    print 'reshaping the images to 5 sets of 10,000 images (RGB - 3*32*32)'
    training_set_images = d.itervalues().next().reshape((5,10000,3,32,32))
    print 'loading image with opencv'
    tmp_img = training_set_images[0][0]
    print tmp_img.dtype # result is uint8

my_main()

我该怎么办？我尝试了所有我在这里看过的东西，但没有任何帮助

特别是，我现在尝试的是使用cv2_img = cv2.imdecode(tmp_img, )中的第二个参数，但结果始终为None