Question

我的html大致看起来像这样：

<h4>Movies</h4>
    <h5><a href="external_link" target="_blank"> A Song For Jenny</a> (2015)</h5>
    Rating: PG<br/>
    Running Time (minutes): 77<br/>
    Description: This Drama, based on real life events, tells the story of a family affected directly by the 7/7 London bombings.  It shows love, loss, heartache and  ...<br/>
    <a href="/bmm/shop/Movie_Detail?movieid=2713288">More about  A Song For Jenny</a><br/>
        <a href="/bmm/shop/Edit_Movie?movieid=2713288">Edit  A Song For Jenny</a><br/>
    <br/>
    <h5><a href="link" target="_blank">#RealityHigh</a> (2017)</h5>
    Rating: PG<br/>
    Running Time (minutes): 99<br/>
    Description: High-achieving high-school senior Dani Barnes dreams of getting into UC Davis, the world's top  veterinary school. Then a glamorous new friend draws  ...<br/>
    <a href="/bmm/shop/Movie_Detail?movieid=4089906">More about #RealityHigh</a><br/>
        <a href="/bmm/shop/Edit_Movie?movieid=4089906">Edit #RealityHigh</a><br/>
    <br/>
    <h5><a href="link" target="_blank">1 Night</a> (2016)</h5>
    Rating: PG<br/>
    Running Time (minutes): 80<br/>
    Description: Bea, a worrisome teenager, reconnects with her introverted childhood friend, Andy. The two  overcome their differences in social status one night aft ...<br/>
    <a href="/bmm/shop/Movie_Detail?movieid=3959071">More about 1 Night</a><br/>
        <a href="/bmm/shop/Edit_Movie?movieid=3959071">Edit 1 Night</a><br/>
    <br/>
    <h5><a href="link" target="_blank">10 Cloverfield Lane</a> (2016)</h5>
    Rating: PG<br/>
    Running Time (minutes): 104<br/>
    Description: Soon after leaving her fiancé Michelle is involved in a car accident. She awakens
to find herself sharing an underground bunker with Howard and Emme ...<br/>
    <a href="/bmm/shop/Movie_Detail?movieid=3052189">More about 10 Cloverfield Lane</a><br/>
        <a href="/bmm/shop/Edit_Movie?movieid=3052189">Edit 10 Cloverfield Lane</a><br/>
    <br/>

我需要使用goquery从这个页面中获取尽可能多的信息。我知道如何提取被单词＆＃34; link＆＃34;取代的外部链接。在这个片段中，我知道如何获得更多细节的链接，但我也想提取仅包含在文本中的信息，即年份（标题），运行时间，缩短描述和PG等级。我无法弄清楚如何在goquery中执行此操作，因为此文本未被任何div或其他标记包围。我试着寻找h5标签，然后在它们上面调用.Next（），但我只能找到<br>标签，而不是中间的文本。我怎样才能做到这一点？如果有比使用goquery更好的方法，我很好。我的代码看起来像这样。

// Retrieve the page count:
    res, err = http.Get("myUrlAddress")
    if err != nil {
        fmt.Println(err)
        os.Exit(-1)
    }
    doc, err = goquery.NewDocumentFromResponse(res)
    if err != nil {
        fmt.Println(err)
        os.Exit(-1)
    }
    links := doc.Find(`a[href*="pageIndex"]`)
    fmt.Println(links.Length()) // Output page count
s := doc.Find("h5").First().Next() // I expect it to be the text after the heading.
fmt.Println(s.Text()) // But it's empty and if I check the node type it says br

Answer 1

我不知道使用正则表达式解析html的想法。我觉得它太脆弱了，不能像标签订单这样的小改动。

我认为最好回到html.Node（golang.org/x/net/html），这是goquery的基础。我们的想法是迭代兄弟姐妹，直到它耗尽，或者遇到下一个h5。处理链接或任何其他元素标签可能有点麻烦，因为html.Node提供了关于属性的相当不友好的api，但是从它切换回goquery更麻烦。

package main

import (
    "fmt"
    "github.com/PuerkitoBio/goquery"
    "golang.org/x/net/html"
    "golang.org/x/net/html/atom"
    "os"
    "strings"
)

type Movie struct {
}

func (m Movie) addTitle(s string) {
    fmt.Println("Title", s)
}

func (m Movie) addProperty(s string) {
    if s == "" {
        return
    }
    fmt.Println("Property", s)
}

var M []*Movie

func parseMovie(i int, s *goquery.Selection) {
    m := &Movie{}
    m.addTitle(s.Text())

loop:
    for node := s.Nodes[0].NextSibling; node != nil; node = node.NextSibling {
        switch node.Type {
        case html.TextNode:
            m.addProperty(strings.TrimSpace(node.Data))
        case html.ElementNode:
            switch node.DataAtom {
            case atom.A:
                //link, do something. You may want to transfer back to go query
                fmt.Println(node.Attr)
            case atom.Br:
                continue
            case atom.H5:
                break loop
            }
        }
    }

    M = append(M, m)
}

func main() {
    r, err := os.Open("movie.html")
    if err != nil {
        panic(err)
    }
    doc, err := goquery.NewDocumentFromReader(r)
    if err != nil {
        panic(err)
    }

    doc.Find("h5").Each(parseMovie)
}

Answer 2

不幸的是，由于这个HTML页面的结构如何，在您确定了包含您示例中的电影列表的页面部分之后，看起来似乎不太有帮助，因为感兴趣的数据点不被孤立到可以被goquery瞄准的元素。

但是，可以使用正则表达式轻松解析详细信息，当然可以根据需要进行修改（特别是当原始页面更改其HTML结构时）。

type Movie struct {
    Title          string
    ReleaseYear    int
    Rating         string
    RuntimeMinutes int
    Description    string
}

var movieregexp = regexp.MustCompile(`` +
    `<h5><a.*?>\s*(.*?)\s*</a>\s*\((\d{4})\)</h5>` + // Title and release year
    `[\s\S]*?Rating: (.*?)<` +
    `[\s\S]*?Running Time \(minutes\): (\d{1,3})` +
    `[\s\S]*?Description: ([\s\S]*?)<`)

// Returns a slice of movies parsed from the given string, possibly empty.
func ParseMovies(s string) []Movie {
    movies := []Movie{}
    groups := movieregexp.FindAllStringSubmatch(s, -1)

    if groups != nil {
        for _, group := range groups {
            // We know these integers parse correctly because of the regex.
            year, _ := strconv.Atoi(group[2])
            runtime, _ := strconv.Atoi(group[4])
            // Append the new movie to the list.
            movies = append(movies, Movie{
                Title:          group[1],
                ReleaseYear:    year,
                Rating:         group[3],
                RuntimeMinutes: runtime,
                Description:    group[5],
            })
        }
    }

    return movies
}

使用goquery从网站检索文本

2 个答案: