Question

使用MERGE (employer:Employer {name: $employerName}) WITH employer UNWIND $names AS name MERGE (employee:Employee {name: name}) MERGE (employer)-[:Employs]->(employee) RETURN *函数，如何在数组中搜索通配符匹配时获得正面结果，如下所示？我目前得到的只是一个负面结果：（ - 1）

indexOf

Answer 1

＆＃13;

var arr = ["OTHER-REQUEST-ASFA","OTHER-REQUEST-ASFB","OTHER-REQUEST-ASFC"]
var a = arr.filter(s => s.includes("ASFB"));
console.log(a);

＆＃13;

Answer 2

var arr = ["OTHER-REQUEST-ASFA","OTHER-REQUEST-ASFB","OTHER-REQUEST-ASFC"]
var searchTerm = "ASFB";

arr.forEach(function(str, idx) {
  if (str.indexOf(searchTerm) !== -1 ){
    console.log(arr[idx] + ' contains "' + searchTerm  + '" at index ' + idx + ' of arr');
  }

});

Answer 3

您需要遍历数组并将indexOf应用于每个单独的字符串，以获得单个输出，您可以使用Array.some，如果数组中的任何元素包含子：

＆＃13;

var arr = ["OTHER-REQUEST-ASFA","OTHER-REQUEST-ASFB","OTHER-REQUEST-ASFC"]

var a = arr.some(s => s.indexOf("ASFB") !== -1)

console.log(a)

＆＃13;

检查数组中的通配符匹配

3 个答案: