我正在清理数据集,需要重新编码许多因子变量。我想使用rlang
和map
创建一个函数来执行此操作。我的示例数据集和代码如下。我想我几乎得到了它,但我似乎无法弄清楚这个bug,可能是因为我没有完全掌握rlang
。
工作数据集:
df1 <- tribble(
~var1, ~var2, ~var3,
"1", "1", "1",
"2", "2", "2",
"3", "3", "3"
)
以下是我将如何重新编码单个变量(以及我想要的结果):
df1 <- df1 %>%
mutate(var1 = fct_recode(var1,
"0" = "1",
"1" = "2",
"2" = "3"))
这是我的工作代码:
recode = function(...){
mutate_quo = quos(...)
map(mutate_quo, ~{
df1 <- df1 %>%
mutate(!!.x = fct_recode(!!.x,
"0" = "1",
"1" = "2",
"2" = "3"))
})
}
这会出现以下错误:
Error: unexpected '=' in:
" df1 <- df1 %>%
mutate(!!.x ="
> "0" = "1",
Error: unexpected ',' in " "0" = "1","
> "1" = "2",
Error: unexpected ',' in " "1" = "2","
> "2" = "3"))
Error: unexpected ')' in " "2" = "3")"
> })
Error: unexpected '}' in " }"
> }
Error: unexpected '}' in "}"
如果删除!!
,函数将编译。但是,当我尝试使用recode("var1")
调用它时,我收到以下错误:
Error in mutate_impl(.data, dots) :
Evaluation error: `f` must be a factor (or character vector)..
我想拥有该功能,然后运行recode(var1, var2, var3)
。
答案 0 :(得分:0)
使用@ epi10提供的建议,这有效但不使用rlang
或map
。
df1 <- df1 %>%
mutate_at(vars(var1, var2, var3),
function(x) case_when(x <= 1 ~ 0,
x <= 2 ~ 1,
x <= 3 ~ 2))