我正在使用python-daemon,但我在守护进程中有一个线程偶尔检查一个串口:
context = daemon.DaemonContext(pidfile=daemon.pidfile.TimeoutPIDLockFile('/var/run/gpstemp.pid'),
uid = 0,
gid = 4,
umask = 0o002,
stdout = sys.stdout, # change these for deployment
stderr =sys.stderr, # change these for deployment
chroot_directory= None,
working_directory='/home/debian/gpstemp'
app = App()
with context:
app.run()
线程运行:
class App():
def __init__(self, port = 5556):
...
# Handle all those threading things
self.__sem = Lock()
self.interval = 60.0 # interval between time updates in seconds
self.worker = Thread(target = self._get_datetime_worker)
def run(self):
self.worker.start()
...
def _get_datetime_worker(self):
while not self.exit.is_set():
self._get_datetime()
self.exit.wait(self.interval)
我正在使用systemctl使用.service文件启动和停止它。 当我跑: sudo systemctl stop myservice
它在返回前等待60秒。如何通过systemctl立即终止服务中的线程。我考虑将上下文传递给App,然后重新定义:
context.signal_map = {
signal.SIGTERM: app.shutdown,
signal.SIGHUP: app.shutdown,
}
然后向App添加关闭方法:
def shutdown(self, *args):
self.exit.set()
self.worker.join()
但是,这不会让上下文破坏PID并且不会退出上下文。我还应该在关机方法中添加什么才能使事情正常工作?
库尔特
答案 0 :(得分:2)
在你杀死主程序时,我是否正确理解你想杀死线程?您可以通过设置daemon=True
:
def run(self):
self.worker.daemon = True
self.worker.start()