Question

我有一个这样的数组：

array(
    [0] => array(
        'date' => '2017-12-20',
        'name' => 'test A',
        'kwa' => 'kwa1, kwa2'
    ),
    [1] => array(
        'date' => '2017-12-20',
        'name' => 'test B',
        'kwa' => ''
    ),
    [2] => array(
        'date' => '2017-12-21',
        'name' => 'test C',
        'kwa' => 'kwa1'
    ),
    [3] => array(
        'date' => '2017-12-22',
        'name' => 'test D',
        'kwa' => ''
    ),
    [4] => array(
        'date' => '2017-12-22',
        'name' => 'test E',
        'kwa' => ''
    ),
)

我希望组中的所有元素都在同一天进入数组。这样的事情：

array(
    ['2017-12-20'] => array( '0', '1'),
    ['2017-12-21'] => array( '2' ),
    ['2017-12-22'] => array( '3', '4' ),
)

PHP有什么功能可以做到这一点？或者有人知道最好的解决方案？谢谢!!!

Answer 1

这是你的解决方案......

输入

<?php 
    $array = array(
        array(
            'date' => '2017-12-20',
            'name' => 'test A',
            'kwa' => 'kwa1, kwa2'
        ),array(
            'date' => '2017-12-20',
            'name' => 'test B',
            'kwa' => ''
        ),array(
            'date' => '2017-12-21',
            'name' => 'test C',
            'kwa' => 'kwa1'
        ),array(
            'date' => '2017-12-22',
            'name' => 'test D',
            'kwa' => ''
        ),array(
            'date' => '2017-12-22',
            'name' => 'test E',
            'kwa' => ''
        ),
    );

<强>解决方案

    $new = array();
    foreach($array as $r){
       $new[$r['date']][] = array('name'=>$r['name'],'kwa' => $r['kwa']); 
    }
    echo "<pre>";print_r($new);

?>

输出

    Array
(
    [2017-12-20] => Array
        (
            [0] => Array
                (
                    [name] => test A
                    [kwa] => kwa1, kwa2
                )

            [1] => Array
                (
                    [name] => test B
                    [kwa] => 
                )

        )

    [2017-12-21] => Array
        (
            [0] => Array
                (
                    [name] => test C
                    [kwa] => kwa1
                )

        )

    [2017-12-22] => Array
        (
            [0] => Array
                (
                    [name] => test D
                    [kwa] => 
                )

            [1] => Array
                (
                    [name] => test E
                    [kwa] => 
                )

        )

)

Answer 2

$arr = array();

foreach($array1 as $key => $item)
{
   $arr[$item['date']][$key] = $key;
}

echo "<pre>";
print_r($arr);

Answer 3

我会使用以下内容：

Try the below code    


getAllByQuery: function (query, callback) {
    this
      .find(query, {campaignId: 1})
      .populate({path: 'campaignId',
        model: 'campaign',
        select: {
          'campaignDetail': 0,
          'area': 0,
        },
        populate: [{
          path: 'ad_Id',
          model: 'Ad',
          select: { 'Level': 1}
        },
        {
          path: 'categories',
          model: 'Category',
          select: { '_id': 0}
        }]
      })
      .exec(callback);
  }

按值分组元素

3 个答案: