如何获取网站上登录用户的名称

Question

如果用户已登录，我希望导航栏中显示用户名，如下所示：

https://i.stack.imgur.com/uRP4R.png

我有一个login.php页面引用（成功登录）到我的Loggedin.php。在此Loggedin页面上，我开始一个新会话并输入

($_SESSION['username']) echo $username;

使用html看起来像这样：

    <a class="right" href="register.php"><span class="glyphicon glyphicon-user"></span> <?php ($_SESSION['username']) echo $username; ?></a>

我知道我可能不会从登录页面获取会话但我无法找到解决方案。

了解更多信息：

的login.php：

 <?php  
session_start();
require('../includes/connect_to_db.php');


if (isset($_POST['username']) and isset($_POST['password'])){

$username = $_POST['username'];
$password = $_POST['password'];

$query = "SELECT * FROM `user` WHERE username='$username' and password='$password'";

$result = mysqli_query($connection, $query) or die(mysqli_error($connection));
$count = mysqli_num_rows($result);

if ($count == 1){
$_SESSION['username'] = $username;
}else{

$fmsg = "Invalid Login Credentials.";
}
}

if (isset($_SESSION['username'])){
header("Location: Loggedin.php");
$username = $_SESSION['username'];
echo "<a href='logout.php'>Logout</a>";
}else{

}

?>

以下是我在loggedin.php页面上尝试的内容：

<?php
//Start Session
session_start();
//Connect to db
require('../includes/connect_to_db.php'); 
//echo the username
 echo $_SESSION['username'];

?>

和echo我使用已经显示的html / php代码实现到导航栏：

<a class="right" href="register.php"><span class="glyphicon glyphicon-user"></span> <?php ($_SESSION['username']) echo $username; ?></a>

Answer 1

如果用户名存储在会话中，则应输出该值：

echo $_SESSION['username'];