Question

例如，我有一个列表a。当我在for循环中执行它时，我可以打印它的所有元素。但是当我在for循环之外执行它时，它只打印最后一个。如何在for循环外打印它们？提前谢谢。

代码：

a=['a is apple','b is banana','c is cherry']
for i in a:
    print(i)
print("====================")
print(i)

打印：

a is apple
b is banana
c is cherry
====================
c is cherry

我想要的结果是：

a is apple
b is banana
c is cherry
====================
a is apple
b is banana
c is cherry

Answer 1

您可以将print与*和换行符的分隔符一起使用：

print(*a, sep='\n')
print("====================")
print(*a, sep='\n')

输出：

a is apple
b is banana
c is cherry
====================
a is apple
b is banana
c is cherry

print(*a)相当于print(a[0], a[1], a[2], ...)。这将打印它之间的空白区域。使用sep='\n'覆盖此默认设置会为您提供换行符。

如果要重复使用它，请编写自己的小辅助函数：

def myprint(a):
    print(*a, sep='\n')

myprint(a)

单行代理，但可读性较差：

print(*(a + ["=" * 20] + a), sep='\n')

输出：

a is apple
b is banana
c is cherry
====================
a is apple
b is banana
c is cherry

在Python 2中，使用以下命令“打开”Python-3样式的打印功能：

from __future__ import print_function

Answer 2

您可以使用join()并将列表传递给它，如下所示：

a=['a is apple','b is banana','c is cherry']
print("\n".join(a))
print("====================")
print("\n".join(a))

输出

a is apple
b is banana
c is cherry
====================
a is apple
b is banana
c is cherry

Answer 3

您可以将列表乘以2并在列表中间添加分隔符，然后使用join方法打印列表。

l = ['a is apple','b is banana','c is cherry']
l = l*2 
#['a is apple', 'b is banana', 'c is cherry', 'a is apple', 'b is banana', 'c is cherry']
l = l.insert(int(len(l)/2), '====================')
#['a is apple', 'b is banana', 'c is cherry', '====================','a is apple', 'b is banana', 'c is cherry']
print('\n'.join(l))

这将输出：

a is apple
b is banana
c is cherry
====================
a is apple 
b is banana
c is cherry

Answer 4

试试这个。这将提供您需要的东西

x,y,z=a
print(x,y,z)

Answer 5

这是最简单，最干净的方法（在Python 2和3中通用）：

print('\n'.join(a + ["===================="] + a))

这是仅限Python-3的版本：

print(*(a + ["===================="] + a), sep='\n')

Python：同时打印列表中的所有字符串

5 个答案: