客户端发送SOAP请求并接收响应

时间：2011-01-25 09:32:23

标签： c# soap webservice-client

尝试创建一个C＃客户端（将作为Windows服务开发），将SOAP请求发送到Web服务（并获取结果）。

从这question我看到了这段代码：

protected virtual WebRequest CreateRequest(ISoapMessage soapMessage)
{
    var wr = WebRequest.Create(soapMessage.Uri);
    wr.ContentType = "text/xml;charset=utf-8";
    wr.ContentLength = soapMessage.ContentXml.Length;

    wr.Headers.Add("SOAPAction", soapMessage.SoapAction);
    wr.Credentials = soapMessage.Credentials;
    wr.Method = "POST";
    wr.GetRequestStream().Write(Encoding.UTF8.GetBytes(soapMessage.ContentXml), 0, soapMessage.ContentXml.Length);

    return wr;
}

public interface ISoapMessage
{
    string Uri { get; }
    string ContentXml { get; }
    string SoapAction { get; }
    ICredentials Credentials { get; }
}

看起来不错，有人知道如何使用它，是否是最佳做法？

7 个答案:

答案 0 :(得分：189)

但是，我通常用另一种方法来做同样的事情

using System.Xml;
using System.Net;
using System.IO;

public static void CallWebService()
{
    var _url = "http://xxxxxxxxx/Service1.asmx";
    var _action = "http://xxxxxxxx/Service1.asmx?op=HelloWorld";

    XmlDocument soapEnvelopeXml = CreateSoapEnvelope();
    HttpWebRequest webRequest = CreateWebRequest(_url, _action);
    InsertSoapEnvelopeIntoWebRequest(soapEnvelopeXml, webRequest);

    // begin async call to web request.
    IAsyncResult asyncResult = webRequest.BeginGetResponse(null, null);

    // suspend this thread until call is complete. You might want to
    // do something usefull here like update your UI.
    asyncResult.AsyncWaitHandle.WaitOne();

    // get the response from the completed web request.
    string soapResult;
    using (WebResponse webResponse = webRequest.EndGetResponse(asyncResult))
    {
        using (StreamReader rd = new StreamReader(webResponse.GetResponseStream()))
        {
            soapResult = rd.ReadToEnd();
        }
        Console.Write(soapResult);        
    }
}

private static HttpWebRequest CreateWebRequest(string url, string action)
{
    HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(url);
    webRequest.Headers.Add("SOAPAction", action);
    webRequest.ContentType = "text/xml;charset=\"utf-8\"";
    webRequest.Accept = "text/xml";
    webRequest.Method = "POST";
    return webRequest;
}

private static XmlDocument CreateSoapEnvelope()
{
    XmlDocument soapEnvelopeDocument = new XmlDocument();
    soapEnvelopeDocument.LoadXml(@"<SOAP-ENV:Envelope xmlns:SOAP-ENV=""http://schemas.xmlsoap.org/soap/envelope/"" xmlns:xsi=""http://www.w3.org/1999/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/1999/XMLSchema""><SOAP-ENV:Body><HelloWorld xmlns=""http://tempuri.org/"" SOAP-ENV:encodingStyle=""http://schemas.xmlsoap.org/soap/encoding/""><int1 xsi:type=""xsd:integer"">12</int1><int2 xsi:type=""xsd:integer"">32</int2></HelloWorld></SOAP-ENV:Body></SOAP-ENV:Envelope>");
    return soapEnvelopeDocument;
}

private static void InsertSoapEnvelopeIntoWebRequest(XmlDocument soapEnvelopeXml, HttpWebRequest webRequest)
{
    using (Stream stream = webRequest.GetRequestStream())
    {
        soapEnvelopeXml.Save(stream);
    }
}

答案 1 :(得分：56)

我得到了这个简单的解决方案here：

在不使用WSDL或代理类的情况下在.NET 4.0 C＃中发送SOAP请求和接收响应： 

class Program
    {
        /// <summary>
        /// Execute a Soap WebService call
        /// </summary>
        public static void Execute()
        {
            HttpWebRequest request = CreateWebRequest();
            XmlDocument soapEnvelopeXml = new XmlDocument();
            soapEnvelopeXml.LoadXml(@"<?xml version=""1.0"" encoding=""utf-8""?>
                <soap:Envelope xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"" xmlns:soap=""http://schemas.xmlsoap.org/soap/envelope/"">
                  <soap:Body>
                    <HelloWorld xmlns=""http://tempuri.org/"" />
                  </soap:Body>
                </soap:Envelope>");

            using (Stream stream = request.GetRequestStream())
            {
                soapEnvelopeXml.Save(stream);
            }

            using (WebResponse response = request.GetResponse())
            {
                using (StreamReader rd = new StreamReader(response.GetResponseStream()))
                {
                    string soapResult = rd.ReadToEnd();
                    Console.WriteLine(soapResult);
                }
            }
        }
        /// <summary>
        /// Create a soap webrequest to [Url]
        /// </summary>
        /// <returns></returns>
        public static HttpWebRequest CreateWebRequest()
        {
            HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(@"http://localhost:56405/WebService1.asmx?op=HelloWorld");
            webRequest.Headers.Add(@"SOAP:Action");
            webRequest.ContentType = "text/xml;charset=\"utf-8\"";
            webRequest.Accept = "text/xml";
            webRequest.Method = "POST";
            return webRequest;
        }

        static void Main(string[] args)
        {
            Execute();
        }
    }

答案 2 :(得分：17)

最佳实践是引用WSDL并将其用作Web服务引用。 它更容易，效果更好，但是如果你没有WSDL，那么XSD定义就是一段很好的代码。

答案 3 :(得分：11)

我写了一个更通用的帮助器类，它接受一个基于字符串的自定义参数字典，这样调用者就可以设置它们而不必对它们进行硬编码。不用说，当您希望（或需要）手动发布基于SOAP的Web服务时，您应该只使用此类方法：在大多数常见场景中，推荐的方法是将Web Service WSDL与添加服务一起使用参考 Visual Studio功能。

using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Net;
using System.Xml;

namespace Ryadel.Web.SOAP
{
    /// <summary>
    /// Helper class to send custom SOAP requests.
    /// </summary>
    public static class SOAPHelper
    {
        /// <summary>
        /// Sends a custom sync SOAP request to given URL and receive a request
        /// </summary>
        /// <param name="url">The WebService endpoint URL</param>
        /// <param name="action">The WebService action name</param>
        /// <param name="parameters">A dictionary containing the parameters in a key-value fashion</param>
        /// <param name="soapAction">The SOAPAction value, as specified in the Web Service's WSDL (or NULL to use the url parameter)</param>
        /// <param name="useSOAP12">Set this to TRUE to use the SOAP v1.2 protocol, FALSE to use the SOAP v1.1 (default)</param>
        /// <returns>A string containing the raw Web Service response</returns>
        public static string SendSOAPRequest(string url, string action, Dictionary<string, string> parameters, string soapAction = null, bool useSOAP12 = false)
        {
            // Create the SOAP envelope
            XmlDocument soapEnvelopeXml = new XmlDocument();
            var xmlStr = (useSOAP12)
                ? @"<?xml version=""1.0"" encoding=""utf-8""?>
                    <soap12:Envelope xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance""
                      xmlns:xsd=""http://www.w3.org/2001/XMLSchema""
                      xmlns:soap12=""http://www.w3.org/2003/05/soap-envelope"">
                      <soap12:Body>
                        <{0} xmlns=""{1}"">{2}</{0}>
                      </soap12:Body>
                    </soap12:Envelope>"
                : @"<?xml version=""1.0"" encoding=""utf-8""?>
                    <soap:Envelope xmlns:soap=""http://schemas.xmlsoap.org/soap/envelope/"" 
                        xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" 
                        xmlns:xsd=""http://www.w3.org/2001/XMLSchema"">
                        <soap:Body>
                           <{0} xmlns=""{1}"">{2}</{0}>
                        </soap:Body>
                    </soap:Envelope>";
            string parms = string.Join(string.Empty, parameters.Select(kv => String.Format("<{0}>{1}</{0}>", kv.Key, kv.Value)).ToArray());
            var s = String.Format(xmlStr, action, new Uri(url).GetLeftPart(UriPartial.Authority) + "/", parms);
            soapEnvelopeXml.LoadXml(s);

            // Create the web request
            HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(url);
            webRequest.Headers.Add("SOAPAction", soapAction ?? url);
            webRequest.ContentType = (useSOAP12) ? "application/soap+xml;charset=\"utf-8\"" : "text/xml;charset=\"utf-8\"";
            webRequest.Accept = (useSOAP12) ? "application/soap+xml" : "text/xml";
            webRequest.Method = "POST";

            // Insert SOAP envelope
            using (Stream stream = webRequest.GetRequestStream())
            {
                soapEnvelopeXml.Save(stream);
            }

            // Send request and retrieve result
            string result;
            using (WebResponse response = webRequest.GetResponse())
            {
                using (StreamReader rd = new StreamReader(response.GetResponseStream()))
                {
                    result = rd.ReadToEnd();
                }
            }
            return result;
        }
    }
}

了解更多信息＆amp;有关此课程的详细信息，您也可以在我的博客上read this post。

答案 4 :(得分：10)

我认为有一种更简单的方法：

 public async Task<string> CreateSoapEnvelope()
 {
      string soapString = @"<?xml version=""1.0"" encoding=""utf-8""?>
          <soap:Envelope xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"" xmlns:soap=""http://schemas.xmlsoap.org/soap/envelope/"">
              <soap:Body>
                  <HelloWorld xmlns=""http://tempuri.org/"" />
              </soap:Body>
          </soap:Envelope>";

          HttpResponseMessage response = await PostXmlRequest("your_url_here", soapString);
          string content = await response.Content.ReadAsStringAsync();

      return content;
 }

 public static async Task<HttpResponseMessage> PostXmlRequest(string baseUrl, string xmlString)
 {
      using (var httpClient = new HttpClient())
      {
          var httpContent = new StringContent(xmlString, Encoding.UTF8, "text/xml");
          httpContent.Headers.Add("SOAPAction", "http://tempuri.org/HelloWorld");

          return await httpClient.PostAsync(baseUrl, httpContent);
       }
 }

答案 5 :(得分：1)

这是我搜索了2天后如何添加名称空间并在不添加代理/服务引用的情况下与SOAP信封一起发出soap请求的最后代码。

class Request
{
    public static void Execute(string XML)
    {
        try
        {
            HttpWebRequest request = CreateWebRequest();
            XmlDocument soapEnvelopeXml = new XmlDocument();
            soapEnvelopeXml.LoadXml(AppendEnvelope(AddNamespace(XML)));

            using (Stream stream = request.GetRequestStream())
            {
                soapEnvelopeXml.Save(stream);
            }

            using (WebResponse response = request.GetResponse())
            {
                using (StreamReader rd = new StreamReader(response.GetResponseStream()))
                {
                    string soapResult = rd.ReadToEnd();
                    Console.WriteLine(soapResult);
                }
            }
        }
        catch (Exception ex)
        {
            Console.WriteLine(ex);
        }
    }

    private static HttpWebRequest CreateWebRequest()
    {
        string ICMURL = System.Configuration.ConfigurationManager.AppSettings.Get("ICMUrl");
        HttpWebRequest webRequest = null;

        try
        {
            webRequest = (HttpWebRequest)WebRequest.Create(ICMURL);
            webRequest.Headers.Add(@"SOAP:Action");
            webRequest.ContentType = "text/xml;charset=\"utf-8\"";
            webRequest.Accept = "text/xml";
            webRequest.Method = "POST";
        }
        catch (Exception ex)
        {
            Console.WriteLine(ex);
        }
        return webRequest;
    }

    private static string AddNamespace(string XML)
    {
        string result = string.Empty;
        try
        {

            XmlDocument xdoc = new XmlDocument();
            xdoc.LoadXml(XML);

            XmlElement temproot = xdoc.CreateElement("ws", "Request", "http://example.com/");
            temproot.InnerXml = xdoc.DocumentElement.InnerXml;
            result = temproot.OuterXml;

        }
        catch (Exception ex)
        {
            Console.WriteLine(ex);
        }

        return result;
    }

    private static string AppendEnvelope(string data)
    {
        string head= @"<soapenv:Envelope xmlns:soapenv=""http://schemas.xmlsoap.org/soap/envelope/"" ><soapenv:Header/><soapenv:Body>";
        string end = @"</soapenv:Body></soapenv:Envelope>";
        return head + data + end;
    }
}

答案 6 :(得分：0)

作为替代方案，与debiasej方法非常接近。由于SOAP请求只是HTTP请求，因此您可以简单地使用HTTP客户端执行GET或POST，但是构建SOAP信封不是强制性的。

类似这样的东西：

using Microsoft.Extensions.Logging;
using System;
using System.Net.Http;
using System.Text;
using System.Threading.Tasks;

namespace HGF.Infraestructure.Communications
{
    public class SOAPSample
    {
        private readonly IHttpClientFactory _clientFactory;
        private readonly ILogger<DocumentProvider> _logger;

        public SOAPSample(ILogger<DocumentProvider> logger,
                          IHttpClientFactory clientFactory)
        {
            _clientFactory = clientFactory;
            _logger = logger;
        }

        public async Task<string> UsingGet(int value1, int value2)
        {
            try
            {
                var client = _clientFactory.CreateClient();
                var response = await client.GetAsync($"https://hostname.com/webservice.asmx/SampleMethod?value1={value1}&value2={value2}", HttpCompletionOption.ResponseHeadersRead);

                //NULL check, HTTP Status Check....

                return await response.Content.ReadAsStringAsync();
            }
            catch (Exception ex)
            {
                _logger.LogError(ex, "Oops! Something went wrong");
                return ex.Message;
            }
        }


        public async Task<string> UsingPost(int value1, int value2)
        {
            try
            {
                var content = new StringContent($"value1={value1}&value2={value2}", Encoding.UTF8, "application/x-www-form-urlencoded");

                var client = _clientFactory.CreateClient();
                var response = await client.PostAsync("https://hostname.com/webservice.asmx/SampleMethod", content);

                //NULL check, HTTP Status Check....

                return await response.Content.ReadAsStringAsync();
            }
            catch (Exception ex)
            {
                _logger.LogError(ex, "Oops! Something went wrong");
                return ex.Message;
            }
        }
    }
}

当然，这取决于您的情况。如果有效载荷过于复杂，则将无法正常工作

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