试图匹配重新

时间:2017-12-21 03:56:29

标签: python regex

我试图使用正则表达式打印它

trying = 'Mar 20th, 2009'

我无法在20日之后打印逗号, 这是我试过的,

print (re.findall(r'(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)[a-z]*[\s]\d{2}[th , ]+', trying))
print (re.findall(r'(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)[a-z]*[\s]\d{2}[a-z,]+', trying))
print (re.findall(r'(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)[a-z]*[\s]\d{2}[a-z]+[,]', trying))

所需的输出应该是输入字符串。 我做错了什么?

2 个答案:

答案 0 :(得分:3)

这将有效

>>> print (re.findall(r'(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)[\s]\d{1,2}th[,][\s]\d{4}',trying))
=> ['Mar 20th, 2009']`

现在让我们看看为什么你的试验没有给你预期的结果

  1. print (re.findall(r'(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)[a-z]*[\s]\d{2}[th , ]+', trying)) - >这在th之后有空格,因此它不匹配

  2. print (re.findall(r'(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)[a-z]*[\s]\d{2}[a-z,]+', trying)) - >通过提供+,您可以通过查找一个或多个th,进行搜索,以便仅匹配到th,

  3. print (re.findall(r'(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)[a-z]*[\s]\d{2}[a-z]+[,]', trying)) - >类似地,您搜索子字符串的结尾为,,因此会发送到th,

答案 1 :(得分:2)

试试这个正则表达式

r'(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec) (?:[0-9]{2}|[0-9])[rdth]{2}, \d{4}'

将与此匹配,

>>> x = re.findall(r'(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec) (?:[0-9]{2}|[0-9])[rdth]{2}, \d{4}', trying)
>>> x
['Mar 20th, 2009']
>>> tryig = 'Jun 3rd, 2017'
>>> x = re.findall(r'(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec) (?:[0-9]{2}|[0-9])[rdth]{2}, \d{4}', tryig)
>>> x
['Jun 3rd, 2017']

根据评论进行更新:

>>> regex = r'(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec) \d{1,2}[rdth]{2}, \d{4}'
>>> x = re.findall(regex, trying)
>>> x
['Mar 20th, 2009']