Question

如何在Windows窗体应用程序C＃中以编程方式创建的PictureBox分配事件处理程序？编辑：

我试过这个，它给出了错误

没有重载pictureBox_MouseDown

this.ListFrameImage[i].MouseDown += new EventHandler(this.pictureBox_MouseDown);

private void pictureBox_MouseDown(object sender, MouseEventArgs e)
{

    someX = e.X;
    someY = e.Y;
    drag = true;
}

Answer 1

只需使用+ =运算符添加事件处理程序：

pictureBox.MouseClick += new MouseEventHandler(your_event_handler);

或者：

pictureBox.MouseClick += new MouseEventHandler((o, a) => code here);

写+ =后按Tab键将生成处理程序。或者你可以写它手动：

pictureBox.MouseClick += pictureBox_MouseClick;

void pictureBox_MouseClick(object sender, MouseEventArgs e)
{
   // blah
}

如何将事件处理程序分配给以编程方式创建的图片框

1 个答案: