Question

我有表格＆＃34; item＆＃34;，＆＃34;付款＆＃34;，＆＃34; join_payment＆＃34;。

该项目有import sys from PyQt5.QtWidgets import (QWidget, QPushButton, QLineEdit, QInputDialog, QApplication, QComboBox, QFrame) import numpy as np class GUI(QWidget): def __init__(self): super().__init__() self.initgui() def initgui(self): # # Set up GUI # self.setGeometry(100, 100, 400, 400) self.move(300, 300) combobox = QComboBox(self) for i in range(1, 10, 1): combobox.addItem(str(i + 1)) combobox.activated[str].connect(self.comboboxchanged) self.setWindowTitle("Testing Easy Setup") self.show() def comboboxchanged(self, text): frame = QWidget(self) frame.hide() for num in range(0, int(text), 1): QLineEdit(frame).move(60, num * 19) frame.show() if __name__ == '__main__': app = QApplication(sys.argv) gui = GUI() sys.exit(app.exec_())，付款方式为@Component( selector: 'box-component', templateUrl: 'box_component.html', directives: const[CORE_DIRECTIVES, BoxComponent] ) class BoxComponent。 join_payment包含行id和id。

付款可能包含许多项目，这些项目将在join_payment表中注册。

我想用这些项目创建日志，我目前正在控制器中执行此操作：

item_id

有没有办法在模型中推出这个？

Answer 1

我建议使用Eloquent关系。 https://laravel.com/docs/5.5/eloquent-relationships#many-to-many。如果您致电联接表item_payment，则会更加轻松：

class Item extends Model {
    public function payments(){
        return $this->belongsToMany(Payments::class)
    }
}

class Payment extends Model {
    public function items(){
        return $this->belongsToMany(Item::class)
    }
}

class ItemPayment extends Model {
    public function item(){
        return $this->belongsTo(Item::class)
    }
    public function payment(){
        return $this->belongsTo(Payment::class)
    }
}

然后，您可以通过多种方式访问所需的数据：

$items = Item::all();
foreach($items as $item){
    $item->payments; //returns all payments belonging to this item
}


$payments = Payment::all();
foreach($payments as $payment){
    $payment->items; //returns all items belonging to this payment
}


$itemPayments = ItemPayment::all();
foreach($itemPayments as $itemPayment){
    $itemPayment->item; //the item for this join
    $itemPayment->payment; //the payment for this join
}

很抱歉更改了您的班级和牌桌名称，但这些约定会让您在Laravel中的生活更轻松

Answer 2

您的项目模型中的

使用此

public function payment()
{
   return $this->hasOne('App\Payment','join_payment','payment_id','item_id');
}

然后在你循环检查

foreach($items as $item){
   dd($item->payment);
}

模型结合Laravel中的两个表

2 个答案: