Question

我有一个pandas数据框，其中一列是文本描述字符串。我需要创建一个新列，以确定列表中的一个字符串是否在文本描述中。

df = pd.DataFrame({'Description': ['2 Bedroom/1.5 Bathroom end unit Townhouse.  
Available now!', 'Very spacious studio apartment available', ' Two bedroom, 1 
bathroom condominium, superbly located in downtown']})

list_ = ['unit', 'apartment']

然后结果应该是

                                        Description    in list
0  2 Bedroom/1.5 Bathroom end unit Townhouse.  Av...    True
1           Very spacious studio apartment available    True
2   Two bedroom, 1 bathroom condominium, superbly...   False

我可以这样做

for i in df.index.values:
    df.loc[i,'in list'] = any(w in df.loc[i,'Description'] for w in list_)

但是使用大量数据集需要的时间比我想要的长。

Answer 1

使用str.contains

list_ = ['unit', 'apartment']
df.Description.str.contains('|'.join(list_))
Out[724]: 
0     True
1     True
2    False
Name: Description, dtype: bool

Answer 2

使用v = df.Description.values.astype('U')[:, None] df['in list'] = (np.char.find(v, list_) > 0).any(1) df Description in list 0 2 Bedroom/1.5 Bathroom end unit Townhouse. Av... True 1 Very spacious studio apartment available True 2 Two bedroom, 1 bathroom condominium, superbly... False -

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在pandas数据框中搜索文本列而不进行循环

2 个答案: