Question

如何在 Sass 的循环中从mixin argument获取array variable？示例代码如下：

＆＃13;

$colors: red green blue;
    $red-foo: 100px;
    $red-bar: 110px;
    $red-baz: 120px;
    $green-foo: 100px;
    $green-bar: 110px;
    $green-baz: 120px;
    $blue-foo: 100px;
    $blue-bar: 110px;
    $blue-baz: 120px;
    
    @mixin item($color-foo, $color-bar, $color-baz){
        width: $color-foo,;
        height: $color-bar;
        ...
    }
    
    @each $color in $colors {
        .class-#{$color}{
            @include item($color#{-foo}, $color#{-bar}, $color#{-baz})
        }
    }

＆＃13;

所需的输出如下：

＆＃13;

    .class-red{
        //variables
    }
    
    .class-green{
        //variables
    }
    
    .class-blue{
        //variables
    }

＆＃13;

还有一种方法可以简化$color-foo, $color-bar, $color-baz @include item($color-shorthand)的缩写吗？也许可以有更好的解决方案。

Answer 1

你想要Sass地图

$colors: (
    red: (
        foo: 100px,
        bar: 110px,
        baz: 110px
    ),
    green: (
        foo: 200px,
        bar: 210px,
        baz: 220px
    ),
    blue: (
        foo: 300px,
        bar: 310px,
        baz: 320px
    )
);

@mixin item ($color-foo, $color-bar, $color-baz) {
    width: $color-foo;
    height: $color-bar;
    padding: $color-baz;
}

@each $name, $value in $colors {
    .class-#{$name} {
        @include item(
            map-get($value, foo),
            map-get($value, bar),
            map-get($value, baz)
        );
    }
}

循环中的Sass动态变量

1 个答案: