我使用python 2.7.14 .....我在python andriod Qpython3版本中编写了这段代码....但是当我在python 2.7.14中使用它时,程序接受带有这些“”或“”的字符串。 .....在Qpython3中我只需要写米......这里我要写“米”..... 任何建议如何解决?
这是代码:
import time
print("This is a converter.Here, you have to spell the whole name of a unit otherwise it wont work")
print(' ')
def converter():
a=float(input("Enter a number:" ))
print(" ")
x=input("from:" )
print(" ")
y=input("to:" )
print(" ")
if x=="meter" and y=="kilometer" or x=="gram" and y=="kilogram":
print(a/1000)
elif x=="kilometer" and y=="meter" or x=="kilogram" and y=="gram":
print(a*1000)
#just keep adding more convertions starting with elifs inside the define function
#and keep the else statement at the end of all elifs...
#and that converter() function call it at the all end just once...
#infact dont do anything escept adding elif statements....good luck
#dont change that float it accepts both integer and float
else :
print("wrong")
print(" ")
print('To continue type "next",Thank you.')
print(" ")
print('To exit type "quit",Thank you.')
print(" ")
s=input()
if s=="next":
print(" ")
converter()
elif s=="quit":
time.sleep(1)
else:
print("I Can't understand your command")
converter()
答案 0 :(得分:0)
您无法在Python 2.x中使用input()
。您应该使用raw_input()
来返回字符串而不是引用变量。
因此,您编辑的代码应如下所示:
import time
print("This is a converter.Here, you have to spell the whole name of a unit otherwise it wont work")
print(' ')
def converter():
a=float(raw_input("Enter a number:" ))
print(" ")
x=raw_input("from:" )
print(" ")
y=raw_input("to:" )
print(" ")
if x=="meter" and y=="kilometer" or x=="gram" and y=="kilogram":
print(a/1000)
elif x=="kilometer" and y=="meter" or x=="kilogram" and y=="gram":
print(a*1000)
#just keep adding more convertions starting with elifs inside the define function
#and keep the else statement at the end of all elifs...
#and that converter() function call it at the all end just once...
#infact dont do anything escept adding elif statements....good luck
#dont change that float it accepts both integer and float
else:
print("wrong")
print(" ")
print('To continue type "next",Thank you.')
print(" ")
print('To exit type "quit",Thank you.')
print(" ")
s=raw_input()
if s=="next":
print(" ")
converter()
elif s=="quit":
time.sleep(1)
else:
print("I Can't understand your command")
converter()
一些改进建议:
1:更好地格式化代码。我已经为你做了。
2:此处:elif s=="quit":
您可以写:import sys
和sys.exit()
退出程序