我从json获取url比我在json解码后得到的url我得到它的html而不是我需要以某种方式发布到url,其中html正文应该发布的内容数组。
URL oracle = new URL("");
try (BufferedReader in = new BufferedReader(
new InputStreamReader(oracle.openStream()))) {
String inputLine1;
while ((inputLine1 = in.readLine()) != null) {
System.out.println(inputLine1);
com.eclipsesource.json.JsonObject object = Json.parse(inputLine1).asObject();
com.eclipsesource.json.JsonArray items = Json.parse(inputLine1).asObject().get("data").asArray();
for (JsonValue item : items) {
//System.out.println(item.toString());
String name = item.asObject().getString("id", "Unknown Item");
System.out.println(name);
String quantity = item.asObject().getString("url", "id");
// JSONArray jsonArray2 = new JSONArray(quantity);
System.out.println(quantity);
/* Platform.runLater(() ->{
try {
Thread.sleep(10000);
} catch (InterruptedException ex) {
Logger.getLogger(HV1.class.getName()).log(Level.SEVERE, null, ex);
}*/
Img.load(quantity);
URL url;
InputStream is = null;
BufferedReader br;
String line;
url = new URL(quantity);
is = url.openStream(); // throws an IOException
br = new BufferedReader(new InputStreamReader(is));
while ((line = br.readLine()) != null) {
System.out.println(line);
//byte[] postData= line.getBytes( StandardCharsets.UTF_8 );
//String[] strArray = new String[] {line};
//System.out.println(strArray[0]);
wb2.load(line);
String originalUrl = "";
String newUrl = originalUrl.replace("ID", name);
System.out.println(newUrl);
URL url1 = new URL(newUrl);
Map<String,Object> params = new LinkedHashMap<>();
params.put("content", line);
params.put("meta", "abc");
StringBuilder postData1 = new StringBuilder();
for (Map.Entry<String,Object> param : params.entrySet()) {
if (postData1.length() != 0) postData1.append('&');
postData1.append(URLEncoder.encode(param.getKey(), "UTF-8"));
postData1.append('=');
postData1.append(URLEncoder.encode(String.valueOf(param.getValue()), "UTF-8"));
byte[] postDataBytes = postData1.toString().getBytes("UTF-8");
HttpURLConnection conn = (HttpURLConnection)url1.openConnection();
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
conn.setRequestProperty("Content-Length", String.valueOf(postDataBytes.length));
conn.setDoOutput(true);
conn.getOutputStream().write(postDataBytes);
Reader in1 = new BufferedReader(new InputStreamReader(conn.getInputStream(), "UTF-8"));
for (int c; (c = in1.read()) >= 0;)
System.out.print((char)c);
/* try{
Thread.sleep(400);
}catch(InterruptedException e){System.out.println(e);} */
}
}
}
}
这是代码,但是这个数据是在字符串中发布而不是在数组中,因为我想在内容数组中发布html内容 这是url中的一个json,我必须发布内容= html页面的主体?
每次我必须在内容数组中发送一次完成时,你可以在输出中看到html中每行html的输出,即答案 0 :(得分:0)
为了发送任何字符串(在您的情况下为HTML字符串),您将不得不使用转义字符。 &#39; /&#39;在JSON的情况下是转义字符。
{
"html": "<div class=\"ad_box\"><img class=\"banner\" src=\"some_ad.png\" alt=\"\" \/>
}
在上面的示例中,我在JSON键中添加了示例html代码&#39; html&#39;并使用&#39; \&#39;作为转义字符忽略双引号(&#34;)。