我的Android应用程序中有一个日历程序。现在,我需要将事件存储在在线Mysql
数据库中,并将它们放在日历上。现在我有一个创建php
对象的json
文件。此JSON
对象显示来自数据库的所有事件
Calendar.php
<?php
include 'DatabaseConfig.php';
// Create connection
//$conn = new mysqli($HostName, $HostUser, $HostPass, $DatabaseName);
$conn = mysqli_connect("localhost", "id2553265_admin", "admin", "id2553265_mobile_app");
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM calendar";
$result = $conn->query($sql);
if ($result->num_rows >0) {
while($row[] = $result->fetch_assoc()) {
$tem = $row;
$json = json_encode($tem);
}
} else {
echo "No Results Found.";
}
echo $json;
$conn->close();
?>
在此代码中,我插入 1496134800000L 以突出显示 2017-05-30 的日期。现在我有了一些突出显示的java代码,并用特定的日期将它们涂成蓝色。
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
View view = inflater.inflate(R.layout.fragment_calendar, container, false);
//calendar setup
compactCalendar = (CompactCalendarView) view.findViewById(R.id.comCalendarView);
compactCalendar.setUseThreeLetterAbbreviation(true);
calendarMonth = (TextView) view.findViewById(R.id.calMonth);
Event may30 = new Event(Color.BLUE, **1496134800000L**, "test");
compactCalendar.addEvent(may30);
Event aug17 = new Event(Color.BLUE, 1502960400000L, "test");
compactCalendar.addEvent(aug17);
compactCalendar.setListener(new CompactCalendarView.CompactCalendarViewListener() {
@Override
public void onDayClick(Date dateClicked){
if (dateFormatDay.format(dateClicked).toString().compareTo("**2017-05-30**") == 0){
Toast.makeText(CalendarFragment.this.getContext(), "There is an event", Toast.LENGTH_SHORT).show();
Intent i = new Intent(getActivity(), ListMay07.class);
i.putExtra("Date", "Sample date");
startActivity(i);
}else if (dateFormatDay.format(dateClicked).toString().compareTo("2017-08-17") == 0){
Toast.makeText(CalendarFragment.this.getContext(), "There is an event", Toast.LENGTH_SHORT).show();
Intent i = new Intent(getActivity(), ListAug17.class);
i.putExtra("Date", "Sample date");
startActivity(i);
}else{
Toast.makeText(CalendarFragment.this.getContext(), "No Event", Toast.LENGTH_SHORT).show();
}
}
@Override
public void onMonthScroll(Date firstDayOfNewMonth) {
calendarMonth.setText(dateFormatMonth.format(firstDayOfNewMonth));
}
});
// Inflate the layout for this fragment
return view;
}
我的主要问题是如何从数据库中获取数据并将其插入到我的java代码中,以便所有事件都将输入数据库而不是实际代码中。
{{3}}
我想通过使用JSON
对象来做到这一点,但我不知道如何做。
[{
"ID":"1",
"Epoch_Time":"1496134800000L",
"Date":"2017-05-30" ,
"Description":"Camaraderie Day"
},
{
"ID":"2",
"Epoch_Time":"1502960400000L",
"Date":"2017-08-17",
"Description":"Sample Date"
}]
答案 0 :(得分:1)
首先为JSON中包含的数据创建POJO。
public class Event{
long id;
long epochTime;
String date;
String desc;
public Event (long id, long epochTime, String date, String desc){
this.id = id;
this.epochTime = epochTime;
this.date = date;
this.desc = desc;
}
}
然后你可以解析JSON并将它存储在POJO
中String myJsonResponse // will contain the json response from the server
try {
JSONArray array = new JSONArray(myJsonResponse);
List<Event> events = new ArrayList<>(array.length());
for (int i = 0; i < array.length(); i++) {
JSONObject object = (JSONObject) array.get(1);
long id = Long.parseLong(object.getString("ID"));
long epoctTime = Long.parseLong(object.getString("Epoch_Time"));
String date = object.getString("Date");
String description = object.getString("Description");
Event event = new Event(id, epoctTime, date, description);
events.add(event);
}
} catch (JSONException e){
e.printStackTrace();
}
然后你可以使用事件列表做任何你想做的事。