Question

我正在尝试查看在SQL Server 2012中向表中插入一些值所花费的时间。

我正在尝试这样做：

DECLARE @starttime DATETIME
DECLARE @timetook DATETIME

CREATE TABLE MyTable (id INT, name CHAR(10));

SET @starttime = SYSDATETIME()

INSERT INTO MyTable (id, name) 
VALUES (1, 'Bob'), (2, 'Peter'), (3, 'Joe'),
       (4, 'Boby'), (5, 'Peters'), (6, 'Joey'),
       (7, 'Bobs'), (8, 'Petery'), (9, 'Joes');

SET @timetook = DATEDIFF(ss, @starttime, SYSDATETIME())

SELECT @timetook

返回1900-01-01 00:00:00.000。根据{{1}} docs，它应为datediff或整数值。因为我花了几秒钟，所以我应该在几秒钟内得到这个数字。（对于此示例，它应为0但没有1900-01-01）

我在这里缺少什么？任何建议将不胜感激。

Answer 1

将@timetook声明为datetime会给你一个datetimeresult。 datetime = 0具体为1900-01-01 00:00:00.000。

declare @starttime datetime
declare @timetook int --Issue was this declaration as datetime

CREATE TABLE MyTable (id int, name char(10));

set @starttime = SYSDATETIME()

INSERT INTO MyTable (id, name) VALUES (1, 'Bob'), (2, 'Peter'), (3, 'Joe'),
                                      (4, 'Boby'), (5, 'Peters'), (6, 'Joey'),
                                      (7, 'Bobs'), (8, 'Petery'), (9, 'Joes');
set @timetook = DATEDIFF(ss, @starttime, SYSDATETIME())

select @timetook

通过将@timetook声明为int，您将获得所需的结果：0

DATEDIFF不返回整数值T-SQL

1 个答案: