我有一个包含一些代码的Song servlet,然后将请求发送到songList.jsp,这样歌曲的标题就会列在页面中。这工作正常。但是,在songList.jsp中,我为每首歌曲定义了一个网址,但是当点击网址时,它会出现:
HTTP Status 404 – Not Found
Description The origin server did not find a current representation for the target resource or is not willing to disclose that one exists.
你知道问题出在哪里吗?
歌曲服务
@WebServlet(name ="Song", urlPatterns = {"/Song"})
// some code
request.setAttribute("result", result);
// some code then send the request
RequestDispatcher view=request.getRequestDispatcher("songList.jsp");
view.forward(request,response);
// songList.jsp
我正在显示页面中的歌曲并且正在显示其正确
<c:forEach items="${result}" var="item" varStatus="status">
<a href="/SongPage?name=${item[0].replace(" ","+")}&id=${item[1]}">${item[0]}</a>
</h4>
<p class="card-text">${item[2]}</p>
</c:forEach>
此链接应转到显示有关歌曲信息的页面,并采用以下格式:
"http://localhost:8080/SongPage?name=Achtung&id=70"
但点击时会出现404错误。
然后我有一个SongPage servlet:
@WebServlet(name ="/SongPage", urlPatterns = {"/SongPage/name/*/id/*"})
public class SongPage extends HttpServlet {
public void init(){
System.out.println("Song Servlet");
}
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
}
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String name = request.getParameter("name").replace("+"," ");
String id = request.getParameter("id");
QueryManager qm = new QueryManager();
ArrayList<ArrayList<String>> result = qm.getSongInfo(name, id);
qm.closeConnections();
ArrayList<String> songInfo = result.get(0);
request.setAttribute("result", songInfo);
RequestDispatcher view=request.getRequestDispatcher("songPage.jsp");
view.forward(request,response);
}
然后我有了songPage.jsp,但对于这个问题不应该很重要。
答案 0 :(得分:2)
确实应该是404. @WebServlet(name ="/SongPage", urlPatterns = {"/SongPage/name/*/id/*"})
比较您上面和上面的urlPatterns您的链接“http://localhost:8080/SongPage?name=Achtung&id=70”。我有基本的想法,关于GET如何发送参数,你会意识到这一点。 ?name=Achtung&id=70
属于GET请求的参数。
尝试@WebServlet(name ="/SongPage", urlPatterns = {"/SongPage"})