Question

我有一个代码，可以动态显示数据库中的书籍类别。我想现在添加另一个功能，如果我点击下拉列表中的任何类别，它应该显示该类别的产品。但我已经有一个显示数据库书籍的主页。我只希望能够点击该类别并更改该特定类别的产品。这是下拉列表的代码：

<?php include "connection.php";

                        $writer_query="SELECT * FROM writer LIMIT 0,5";
                        $run_query= mysqli_query($conn, $writer_query);
                        if(mysqli_num_rows($run_query)>0){
                        while($row=mysqli_fetch_array($run_query)){
                            $wid=$row["w_id"];
                            $wname=$row["w_name"];
                            echo"
                            <a class='nav-link bottom' id='v-pills-profile-tab' data-toggle='pill' href='#v-pills-profile' role='tab' aria-controls='v-pills-profile' aria-selected='false'>$wname</a>
                            ";
                        }}
                        ?>

以下是我在主页上显示图书的代码：

<div class="card-body">
    <div class="card-deck">
    <?php include"connection.php";
    $book_query="SELECT b.*, w.* FROM books as b INNER JOIN writer as w on b.b_writer = w.w_id ORDER BY RAND() LIMIT 8";
    $run_query= mysqli_query($conn, $book_query);
    if(mysqli_num_rows($run_query)>0){
    while($row=mysqli_fetch_array($run_query)){
    $bid=$row["b_id"];
    $bname=$row["b_name"];
    $bisbn=$row["b_isbn"];
    $bwriter=$row["w_name"];
    $bprice=$row["b_price"];
    $bdesc=$row["b_desc"];
    $bimg=$row["b_img"];
    ?>
    <div class="col-md-3 col-sm-6 mt-4">
    <div class="card text-center ">
    <img class="card-img-top img-thumbnail img-thumb" src="<?php echo"$bimg";?>" alt="Dune">
    <div class="card-body">
    <h6 class="card-title"><?php echo"$bname";?></h6>
    <footer class="blockquote-footer">By <cite title="<?php echo $bwriter;?>"><?php echo"$bwriter";?></cite></footer>
    <p class="card-text">Price: &#8377; <?php echo"$bprice";?></p>                  
    <a href="#" class="btn btn-primary" data-toggle="modal" data-target="#buy">Buy</a>
    <input type="button"  value="Details" id="<?php echo $row["b_id"]; ?>" class="btn btn-primary view_data" />
    </div>          
    </div>      
    </div>
    <?php }} ?>
    </div>
    </div>

Answer 1

您需要将类别ID存储到锚标记中。像http://www.example.com/home?cat_id=2

一样

通过使用此功能，您可以在另一个页面上获取该类别ID并获取URL的参数。

现在你需要wrire代码和查询

If(!empty(cat_id)) {

//, HERE IS YOUR QUERY AND RETURN ARRAY

}

单击类别链接时显示类别

1 个答案: