Question

使用ASPNet Boilerplate，并使用以下代码返回pagedResultSetDto，如何显示页面链接？

 public PagedResultDto<ArticleDto> GetAll()
    {
        var articleCount = articleRepository.Count();

        var t = articleRepository.GetAllIncluding(x => x.articleImage).Include(x => x.Category).Where(
                x => x.PublishFrom <= DateTime.Now &&
                x.PublishTo >= DateTime.Now &&
                 x.Status == PostStatus.Published &&
                 x.IsDeleted == false
                ).OrderByDescending(x=> x.PublishFrom).ToList();

        return new PagedResultDto<ArticleDto>
        {
            TotalCount = articleCount,
            Items = t.MapTo<List<ArticleDto>>()
        };
    }

Answer 1

首先，输入IPagedResultRequest作为输入：

// using Abp.Linq.Extensions;

public PagedResultDto<ArticleDto> GetAll(PagedResultRequestDto input)
{
    var articleCount = articleRepository.Count();

    var t = articleRepository
            .GetAllIncluding(x => x.articleImage)
            .Include(x => x.Category)
            .Where(x =>
                x.PublishFrom <= DateTime.Now &&
                x.PublishTo >= DateTime.Now &&
                x.Status == PostStatus.Published &&
                x.IsDeleted == false
            )
            .OrderByDescending(x => x.PublishFrom)
            .PageBy(input) // Page by SkipCount and MaxResultCount
            .ToList();

    return new PagedResultDto<ArticleDto>
    {
        TotalCount = articleCount,
        Items = t.MapTo<List<ArticleDto>>()
    };
}

然后创建自己的链接以传递SkipCount，例如第2页GetAll?SkipCount=10。

MaxResultCount的{{3}} 10。

Answer 2

您可以根据GetAll（）的结果来计算它。您可以请求所需的记录数。让我们说10（默认值）。它返回TotalCount和Items（=记录）。让我们说TotalCount = 95.除以95/10 = 9.5~ =＆gt; 10页。显示10个链接。虽然9页将显示10条记录，但最后一页将有5条记录。这

如何使用和显示PagedResultDto

2 个答案: