Question

我现在拥有的东西：我目前有一个公共课“MainMenu”，在那里我向用户致意并要求他们输入一组数字（1-10）以获取他们喜欢的选项执行。这是由Switch案例决定的。

在每个案例中，要么运行一个小的执行，要么指向一个单独的类。

例如：

    public static void mainMenu(Scanner sc) {
    //Scanner sc = new Scanner(System.in);
    System.out.println("Welcome to the Flight Scheduler!\n");
    System.out.println("Please remember to always use U, M, T, W, R, F, S, for entering");
    System.out.println("the day of the week, and to always use military time");
    System.out.println("for entering the time.");
    System.out.println("Please make your choice\nby entering the corresponding menu number:\n");

    System.out.println("1.\tSet Clock");
    System.out.println("2.\tClear Schedule");
    System.out.println("3.\tAdd Airline");
    System.out.println("4.\tAdd Flight");
    System.out.println("5.\tCancel Flight");
    System.out.println("6.\tShow Flight Info");
    System.out.println("7.\tShow Departures");
    System.out.println("8.\tShow Arrivals");
    System.out.println("9.\tFind Flights Between Two Airports");
    System.out.println("10.\tExit\n");

    int userChoice = sc.nextInt();

    switch (userChoice) {
      case 1:
      AirlineAircraftData.AddAirline(sc);
      break;

这将执行我的 AddAirline 方法，我想将对象返回主菜单，并允许用户在输入后立即继续从之前提供的10个选项中进行选择 AddAirline 方法请求的字段。

以下是我在用户选择后运行的方法：

    public static A8AirlineAircraftData AddAirline(Scanner sc) {
    sc.nextLine();
    System.out.println("Please enter the Airline name:");
    String airName = sc.nextLine();

    System.out.println("Please enter the Airline code:");
    String airCode = sc.nextLine();
    System.out.println("Please enter the Delta Aircraft:");
    String airCraft = sc.nextLine();
    System.out.println("Please enter the first class seat capacity:");
    int firstClass = sc.nextInt();
    System.out.println("Please enter the business class seat capacity:");
    int busiClass = sc.nextInt();
    System.out.println("Please enter the economy class seat capacity:");
    int econClass = sc.nextInt();
    System.out.println("Airline name: " + airName);
    System.out.println("Airline code: " + airCode);
    System.out.println("Delta Aircraft: " + airCraft);
    //Splitting the first word from the rest of the string
    String arr[] = airCraft.split(" ", 2);
    String firstWord = arr[0];
    System.out.println(firstWord + " first class seat capacity: " + firstClass);
    System.out.println(firstWord + " business class seat capacity: " + busiClass);
    System.out.println(firstWord + " economy class seat capacity: " + econClass);
    //Airline object
    A8AirlineAircraftData airline = new A8AirlineAircraftData(airName, airCode, airCraft, firstClass, busiClass, econClass);
    System.out.println(airName + " successfully added. Press Enter to continue.");
    sc.nextLine();//Press Enter to continue
    sc.nextLine();   
    //A8MainMenu.mainMenu(sc); //return to main menu after Enter. 
    return airline;

感谢您的帮助，我是一名新手，我知道我正在做的很多事情并不一定有意义。

Answer 1

由于@D M，我能够弄清楚如何解决这个问题。我只是将整个主菜单包裹在退出＆＃39; 10＆＃39;的do-while循环中。

在运行方法并检索“返回”后，如何返回主菜单？无法理解'getter'

1 个答案: