Question

我有一个项目列表，我想返回一个最严重的项目，即输入可能是＆＃34; Rainy | Icy | Windy＆＃34;

并且可能的输入列表（按严重程度排列）：晴天，阴天，刮风，下雨，结冰。

通过上面的输入，我想输出Icy，因为它是最严重的。

我尝试过类似的事情：

dictionary1 = {'sunny': 0, 'cloudy': 1, 'windy': 1, 'rainy': 2, 'icy': 3}
    with open(Conditions_csv, 'wb') as fw:
        writer = csv.writer(fw, delimiter=',')
        header = ['Date','latitude','longitude','Condition']
        writer.writerow(header)
        for row in cur.fetchall():
            conditions = row[3].split("|")


        for item in sorted(dictionary1.keys(),reverse= True):
            name = dictionary1[item]
            if name in conditions:
                print row
                print name
                writer.writerow(row + name)
db.close()

上面的输出将是：

(18/12/2017,45,-85, Rainy|Icy|Windy)
Icy
(18/12/2017,45,-85, Rainy|Icy|Windy)
Rainy
(18/12/2017,45,-85, Rainy|Icy|Windy)
Windy
(18/12/2017,47,-88, Rainy|Windy)
Rainy
(18/12/2017,47,-88, Rainy|Windy)
Windy
(18/12/2017,40,-84, Icy|Windy)
Icy
(18/12/2017,40,-84, Icy|Windy)
Windy

所有我想要重申的是：

(18/12/2017,45,-85, Rainy|Icy|Windy)
Icy
(18/12/2017,47,-88, Rainy|Windy)
Rainy
(18/12/2017,40,-84, Icy|Windy)
Icy

Answer 1

内置的max函数允许您传递一个可选的key参数，该参数执行我认为您要求的参数：

>>> severities = {'sunny': 0, 'cloudy': 1, 'windy': 1, 'rainy': 2, 'icy': 3}
>>> max(['sunny', 'cloudy', 'windy', 'rainy', 'icy'], key=lambda s: severities[s])
'icy'

Answer 2

以下是我用于答案的原因：FYI：

with open(Conditions_csv, 'wb') as fw:
    writer = csv.writer(fw, delimiter=',')
    header = ['Date','latitude','longitude','Condition']
    writer.writerow(header)
    for row in cur.fetchall():
        conditions = row[3].split("|")
        Final = max(conditions, key=lambda s: dictionary[s])
        myList= row[0],float(row[1]),float(row[2]),Final
        writer.writerow(myList)
db.close()

查找列表中的文本以在python中查找最大值

2 个答案: