我有两张桌子:
__表R _____
ID.....CustID....DATE
1......1.........2000-01-01
2......2.........2000-01-02
3......2.........2000-01-03
4......2.........2000-02-22
5......1.........2000-03-23
__表客户______
ID....NAME
1.....Lucas
2.....Michael
请问,我怎么能做一个SELECT,它会从每个客户的NAME返回最后日期? (这样):
Lucas......2000-03-23
Michael....2000-02-22
答案 0 :(得分:0)
您可以使用:
select c.name, max(r.date)
from table_customers c
join table_r r on r.custid = c.id
group by c.id, c.name;
答案 1 :(得分:0)
您需要的选择,使用MAX将返回最新日期:
SELECT customer.name, MAX(r.date)
两张表中的join:
FROM r INNER JOIN customer ON r.custid = customer.id
但是,如果您需要每个客户的最新日期,则需要group:
GROUP BY r.custid;
答案 2 :(得分:0)
select c.name, r.date
from table_customers c
join table_r r on r.custid = c.id
ORDER BY r.date DESC
LIMIT 2 ;