Question

我的方法是：

public String changeCurrentDate(Integer variant){
    String currentTime = TestApp.getInstance().getDriver().findElement(By.id("common.HeaderComponent.mainLayout.serverTimeLabel")).getText();
    String currentDate = currentTime.substring(0, 10);
    System.out.println("currentDate " +currentDate);
    String date = null;
    DateFormat df = new SimpleDateFormat("dd/mm/yyyy");
    try{
        Date date3 = df.parse(currentDate);
        df.format(date3);
        System.out.println("date3 " +date3);
        Date previousDate = DateUtils.addDays(date3, variant);
        date = previousDate.toString();
        return date;
    }catch (Exception e){
    }
    return date;
}

注意：currentTime变量的值始终为＆＃34; 18/12 / 2017＆＃34; 我希望以dd / mm / yyyy格式显示日期结果。但它始终给出＆＃34; Wed Jan 18 00:12:00 IST 2017＆＃34;像这样。

运行时间结果：

currentDate 18/12/2017
date3 Wed Jan 18 00:12:00 IST 2017

Answer 1

您应该返回格式化日期，而不是日期的toString（）。试试这个：

Date previousDate = DateUtils.addDays(date3, variant);
return df.format(previousDate);

Answer 2

df.format只返回应用了格式的Date的String表示，因此代码中的行无效。

尝试更改代码以改为使用格式化输出：

public String changeCurrentDate(Integer variant){
    String currentTime = TestApp.getInstance().getDriver().findElement(By.id("common.HeaderComponent.mainLayout.serverTimeLabel")).getText();
    String currentDate = currentTime.substring(0, 10);
    System.out.println("currentDate " +currentDate);
    DateFormat df = new SimpleDateFormat("dd/mm/yyyy");
    Date date3 = df.parse(currentDate);
    System.out.println("date3 " + df.format(date3));
    Date previousDate = DateUtils.addDays(date3, variant);
    return previousDate.toString();
}

此外 - 它很难捕获异常，所以你应该删除它。

Answer 3

我们应该总是试图找出更方便的方式，以便我们可以进一步使用它。在这种情况下，我们可以使用以下方法：

Private Async Sub Timer1_Tick(sender As Object, e As EventArgs) Handles Timer1.Tick 

    Try

        Dim jsonName = New IO.StreamReader(DirectCast(Await DirectCast(Net.WebRequest.Create("https://www.googleapis.com/youtube/v3/channels?part=snippet&id=" & ChannelID & "&fields=items(id%2Csnippet(title))&key=AIzaSyA1n4M-fo2Y5NHUj0RsvXEAis3H6_lIjRg"), Net.HttpWebRequest).GetResponseAsync, Net.HttpWebResponse).GetResponseStream)
        Dim rqn As Newtonsoft.Json.Linq.JToken = Newtonsoft.Json.Linq.JObject.Parse(jsonName.ReadToEnd)
        ChannelName = $"{rqn.SelectToken("items")(0)("snippet")("title")}"

        Label3.Text = ChannelName

        Dim json = New IO.StreamReader(DirectCast(Await DirectCast(Net.WebRequest.Create("https://www.googleapis.com/youtube/v3/channels?part=statistics&id=" & ChannelID & "&fields=items(statistics(subscriberCount))&key=AIzaSyA1n4M-fo2Y5NHUj0RsvXEAis3H6_lIjRg"), Net.HttpWebRequest).GetResponseAsync, Net.HttpWebResponse).GetResponseStream)
        Dim rq As Newtonsoft.Json.Linq.JToken = Newtonsoft.Json.Linq.JObject.Parse(json.ReadToEnd)
        Subs = $"{Convert.ToDecimal(rq.SelectToken("items")(0)("statistics")("subscriberCount")).ToString("#,###,###")}"

        Label1.Text = Subs

    Catch ex As Exception

        Timer1.Stop()
        MessageBox.Show("Erro ao tentar Conseguir os Dados do Canal!")

    End Try

End Sub

您可以轻松调用此方法，如下所示：

public String dateString(String input) {        
    SimpleDateFormat parser = new SimpleDateFormat("EEE MMM d HH:mm:ss zzz yyyy");
    String formattedDate = "";        
    try {
        Date date = parser.parse(input);
        SimpleDateFormat formatter = new SimpleDateFormat("dd/MM/yyyy");
        formattedDate = formatter.format(date);         
    } catch (ParseException e) {            
        e.printStackTrace();
    }

    return formattedDate;
}

返回如下输出：

Date date3 = df.parse(currentDate);
df.format(date3);

String input = date3.toString();            
String requiredDate = dateString(input);

System.out.println("requiredDate: "+ requiredDate);

如何使用SimpleDateFormat获取所需的日期格式

3 个答案: