Question

我有三张桌子financial_year，house_details，consumer_details。我需要按年度和子收入来获得每个税收组的总和。我的表格和查询位于以下链接：sqlfiddle

获得结果：

Name  house_number  address  subincome   financial_year  gtax  htax  LTAX
--------------------------------------------------------------------------
Bala  22            Mumbai   Garbage tax 2015-2016       200   NULL  NULL
Bala  22            Mumbai   Garbage tax 2016-2017       250   NULL  NULL
Bala  22            Mumbai   House tax   2015-2016       NULL  0     NULL
Bala  22            Mumbai   House tax   2016-2017       NULL  145   NULL
Bala  22            Mumbai   Light tax   2015-2016       NULL  NULL  510
Bala  22            Mumbai   Light tax   2016-2017       NULL  NULL  200

期待结果：

Name    house_number    address    gtax    htax    LTAX
--------------------------------------------------------
Bala    22              Mumbai     450     145     710

Answer 1

试试这个它会得到你想要的确切结果，我只是创建一个驱动器表然后求和

SELECT name
     , house_number
     , address
     , SUM(gtax) as gtax
     , SUM(htax) as htax
     , SUM(LTAX) LTAX
FROM (SELECT c.consumer_name as Name
           , c.house_number
           , c.address,h.subincome
           , h.financial_year
           , CASE WHEN h.subincome = 'Garbage tax' THEN f.garbage_tax - sum(h.rupees)END as gtax
           , CASE WHEN h.subincome = 'House tax' THEN f.house_tax - sum(h.rupees) END as htax
           , CASE WHEN h.subincome = 'Light tax' THEN f.light_tax - sum(h.rupees) END as LTAX
      FROM house_details h
          INNER JOIN financial_year f ON h.financial_year = f.year AND h.house_id = f.house_number
          INNER JOIN consumer_details c ON h.house_id = c.house_number AND h.financial_year != '2017-2018'
      GROUP BY h.subincome, h.financial_year) as main
GROUP BY house_number

然后结果是： Screenshot of result

Answer 2

您正在寻找条件汇总注释此解决方案仅适用于每个财政年度的房屋详细信息中每个子收入（税收类型）的条目。

SELECT c.consumer_name as Name, c.house_number, c.address,
sum(CASE WHEN h.subincome = 'Garbage tax' THEN f.garbage_tax else 0 end) - 
sum(CASE WHEN h.subincome = 'Garbage tax' THEN h.rupees else 0 END) as gtax, 
sum(CASE WHEN h.subincome = 'House tax' THEN f.house_tax else 0 end) -
sum(CASE WHEN h.subincome = 'House tax' THEN h.rupees else 0 END) as htax, 
sum(CASE WHEN h.subincome = 'Light tax' THEN f.light_tax else 0 end) - 
sum(CASE WHEN h.subincome = 'Light tax' THEN h.rupees else 0 END) as LTAX 
from house_details h 
INNER JOIN financial_year f ON h.financial_year = f.year AND h.house_id = f.house_number 
INNER JOIN consumer_details c ON h.house_id = c.house_number AND h.financial_year != '2017-2018' 
group by c.consumer_name , c.house_number, c.address

结果

+------+--------------+---------+------+------+------+
| Name | house_number | address | gtax | htax | LTAX |
+------+--------------+---------+------+------+------+
| Bala | 22           | Mumbai  |  450 |  145 |  710 |
+------+--------------+---------+------+------+------+
1 row in set (0.03 sec)

如果无法保证在每个财政年度都会有每个子收入的条目，那么解决方案必须从税收到期表（财政年度）开始，在我看来，这是一个设计糟糕，不灵活并迫使次优解

select c.consumer_name as Name, s.house_number, c.address,
        sum(case when subincome = 'garbage tax' then taxdue else 0 end) - sum(case when subincome = 'garbage tax' then taxpaid else 0 end) as gtax,
        sum(case when subincome = 'house tax' then taxdue else 0 end) - sum(case when subincome = 'house tax' then taxpaid else 0 end) as htax,
        sum(case when subincome = 'light tax' then taxdue else 0 end) - sum(case when subincome = 'light tax' then taxpaid else 0 end) as ltax
from 
(
SELECT  F.`house_number`, F.`year`, F.`house_tax` taxdue, F.`createdAt`, F.`updatedAt`,ifnull(h.subincome,'house_tax') subincome,ifnull(H.RUPEES,0) taxpaid
FROM FINANCIAL_YEARS F
LEFT  JOIN house_details H ON H.HOUSE_ID = F.HOUSE_NUMBER AND H.SUBINCOME = 'house tax' and f.year = h.financial_year
#where f.house_number = 22
union all
SELECT F.`house_number`, F.`year`, F.`light_tax`,  F.`createdAt`, F.`updatedAt`,ifnull(h.subincome,'light tax'),ifnull(H.RUPEES,0) 
FROM FINANCIAL_YEARS F
LEFT  JOIN house_details H ON H.HOUSE_ID = F.HOUSE_NUMBER AND H.SUBINCOME = 'light tax' and f.year = h.financial_year
#where f.house_number = 2
union all
SELECT F.`house_number`, F.`year`, F.`garbage_tax`, F.`createdAt`, F.`updatedAt`,ifnull(h.subincome,'garbage tax'),ifnull(H.RUPEES,0) 
FROM FINANCIAL_YEARS F
LEFT  JOIN house_details H ON H.HOUSE_ID = F.HOUSE_NUMBER AND H.SUBINCOME = 'garbage tax' and f.year = h.financial_year
#where f.house_number = 2
) s
join consumer_details c on s.house_number = c.house_number
where s.year <> '2017-2018'
group by c.consumer_name , s.house_number, c.address

使用mysql组的总和

2 个答案: