Question

我需要一个.NET正则表达式来匹配来自"[@foo]"的{{1}} w / c我已经可以使用模式"applicant_data/contact_number[@foo]"进行匹配。

但是我想做一个例外，以便"\[@(.*?)\]"与模式不匹配。所以问题是正则表达式应该是什么，以便它将获得任何有效的字母数字（[@ bar]，[@ theVar]，[@ zoo $ 6]）但不是[@ bar = 1]，[@ theVar = 3] ？

Answer 1

试试这个正则表达式：

\[@(?![^\]]*?=).*?\]

Click for Demo

<强>解释

\[@ - 按字面意思匹配[@
(?![^\]]*?=) - 负面预测确保=在下一个]之前的任何地方都不存在
.*? - 匹配除换行符之外的任何字符的出现次数
\] - 按字面意思匹配]

Answer 2

你可以试试这个：

\[@[\w-]+(?!=)\]

解释：

"\[" &       ' Match the character “[” literally
"@" &        ' Match the character “@” literally
"[\w-]" &    ' Match a single character present in the list below
                ' A “word character” (Unicode; any letter or ideograph, digit, connector punctuation)
                ' The literal character “-”
   "+" &        ' Between one and unlimited times, as many times as possible, giving back as needed (greedy)
"(?!" &      ' Assert that it is impossible to match the regex below starting at this position (negative lookahead)
   "=" &        ' Match the character “=” literally
")" &
"\]"         ' Match the character “]” literally

希望这有帮助！

正则表达式排除特定字符串

2 个答案: