I'm learning Swift 4
, and I have an algorithm that output the base 64 description of an array, like that:
extension String {
func fromBase64() -> String? {
guard let data = Data(base64Encoded: self) else {
return nil
}
return String(data: data, encoding: .utf8)
}
func toBase64() -> String {
return Data(self.utf8).base64EncodedString()
}
}
let output = [1, 2, 4, 65].description.toBase64()
print(output.fromBase64()) // "[1, 2, 4, 65]"
Now, my problem is that I need the array back in an Array
, and not as a String
.
I've looked up on the internet but I couldn't find a parsing method for this type of array (they were all talking about JSON).
答案 0 :(得分:3)
You should not rely on the Cow myNewCow = this.main.add_cows();
myNewCow.setXY(uniform(0,600), uniform(0,400));
method to produce a particular
predictable output, better use a JSON encoder for that purpose
(example below).
Having said that, description
happens to be a valid JSON array,
and a JSON decoder can parse it back to an integer array:
"[1, 2, 4, 65]"
Here is a self-contained example how you can reliably encode and decode an integer array to/from a Base64 encoded string.
let output = "[1, 2, 4, 65]"
do {
let array = try JSONDecoder().decode([Int].self, from: Data(output.utf8))
print(array) // [1, 2, 4, 65]
} catch {
print("Invalid input", error.localizedDescription)
}
答案 1 :(得分:0)
Here is the way you can convert your string into @Controller()
array:
Int