Question

我有这些元素类：

public class DataclassModeloSD
{
    public T001 tablaT001 { get; set; }
    public T001W tablaT001W { get; set; }
    public TSPAT tablaTSPAT { get; set; }
}

和其他课程：

public class T001
{
    public string BUKRS { get; set; }
    public string BUTXT { get; set; }
}

public class T001W
{
    public string WERKS { get; set; }
    public string NAME1 { get; set; }
}

public class TSPAT
{
    public string SPART { get; set; }
    public string VTEXT { get; set; }
}

请问，如何向List<DataclassModeloSD>添加元素？我想用JSON格式填写一个返回列表。

感谢。

Answer 1

我认为你的意思是创建一个新的List<DataclassModeloSD>对吗？在这种情况下，您必须创建列表中的元素并使用方法Add()。像这样：

var yourList = new List<DataclassModeloSD>();

yourList.Add(new DataclassModeloSD(){
    tablaT001 = new T001(){
        BUKRS = "Foo",
        BUTXT = "Bar"
    },
    tablaT001W = new T001W(){
        WERKS= "Foo",
        NAME1 = "Bar"
    },
    tablaTSPAT = new TSPAT(){
        SPART = "Foo",
        VTEXT = "Bar"
    }
});

Answer 2

你可以在这样的声明中做到这一点，

var list = new List<DataclassModeloSD>()
   {
      new DataclassModeloSD()
         {
            tablaT001 = new T001()
               {
                  BUKRS = "asdasd",
                  BUTXT = "dassdf"
               },
            tablaT001W = new T001W()
               {
                  NAME1 = "asdfsdf",
                  WERKS = "sdfsdf'
               },
            tablaTSPAT = new TSPAT()
               {
                  SPART = "dsfsdf",
                  VTEXT = "sdfdfg"
               }
         },
      new DataclassModeloSD()
         {
            tablaT001 = new T001()
               {
                  BUKRS = "hjkhjk",
                  BUTXT = "dfg"
               },
            tablaT001W = new T001W()
               {
                  NAME1 = "ghjhj",
                  WERKS = "jkl'
               },
            tablaTSPAT = new TSPAT()
               {
                  SPART = "fgh",
                  VTEXT = "dfg"
               }
         }
   };

或其他类似的方式

var tablaT001 = new T001()
   {
      BUKRS = "asdasd",
      BUTXT = "dassdf"
   };
var tablaT001W = new T001W()
   {
      NAME1 = "asdfsdf",
      WERKS = "sdfsdf'
   };
var tablaTSPAT = new TSPAT()
   {
      SPART = "dsfsdf",
      VTEXT = "sdfdfg"
   };

var dataclassModeloSD = new DataclassModeloSD();
dataclassModeloSD.tablaT001 = tablaT001;
dataclassModeloSD.tablaT001W = tablaT001W;
dataclassModeloSD.tablaTSPAT = tablaTSPAT;

list.Add(dataclassModeloSD);

或添加多个项目的另一个例子

var modeloSD1 = new DataclassModeloSD()
     {
        tablaT001 = new T001()
           {
              BUKRS = "asdasd",
              BUTXT = "dassdf"
           },
        tablaT001W = new T001W()
           {
              NAME1 = "asdfsdf",
              WERKS = "sdfsdf'
           },
        tablaTSPAT = new TSPAT()
           {
              SPART = "dsfsdf",
              VTEXT = "sdfdfg"
           }
     };
var modeloSD2 = new new DataclassModeloSD()
     {
        tablaT001 = new T001()
           {
              BUKRS = "hjkhjk",
              BUTXT = "dfg"
           },
        tablaT001W = new T001W()
           {
              NAME1 = "ghjhj",
              WERKS = "jkl'
           },
        tablaTSPAT = new TSPAT()
           {
              SPART = "fgh",
              VTEXT = "dfg"
           }
     };

list.Add(modeloSD1);
list.Add(modeloSD2);

但是请注意：这是非常简单的事情，并且有很多资源可用于此级别的编码。请务必在互联网上搜索，因为您将学到很多东西，而不仅仅是在您理解的时候提出问题。

如何将项目添加到具有其他类的类中

2 个答案: