Question

我确实有我的联系人ID。有没有办法可以获得联系人的所有细节（借助联系人ID）？

Stack Over流程中已经存在question相同的但是答案似乎已经过时且不再有效。

Answer 1

使用联系人ID获取联系人详细信息的代码段。

public static ModelContact getContactDetails(final Context context, String contactId) {

        ModelContact contact = new ModelContact();
        contact.setContactId(contactId);

        Cursor cursor = context.getContentResolver().query(ContactsContract.Data.CONTENT_URI,
                new String[]{ContactsContract.Data._ID,
                        ContactsContract.Data.MIMETYPE,
                        ContactsContract.Data.DISPLAY_NAME,
                        ContactsContract.Data.RAW_CONTACT_ID,
                        ContactsContract.Data.LOOKUP_KEY,
                        ContactsContract.Data.DATA1,
                        ContactsContract.Data.DATA2,
                        ContactsContract.Data.DATA3,
                        ContactsContract.Data.DATA4,
                        ContactsContract.Data.DATA5,
                        ContactsContract.Data.DATA6,
                        ContactsContract.Data.DATA7,
                        ContactsContract.Data.DATA8,
                        ContactsContract.Data.DATA10},

                ContactsContract.Data.CONTACT_ID + "=?" + " AND "
                        + "(" + ContactsContract.Data.MIMETYPE + "='" + ContactsContract.CommonDataKinds.Phone.CONTENT_ITEM_TYPE + "' OR "
                        + ContactsContract.Data.MIMETYPE + "='" + ContactsContract.CommonDataKinds.StructuredName.CONTENT_ITEM_TYPE + "' OR "
                        + ContactsContract.Data.MIMETYPE + "='" + ContactsContract.CommonDataKinds.StructuredPostal.CONTENT_ITEM_TYPE + "' OR "
                        + ContactsContract.Data.MIMETYPE + "='" + ContactsContract.CommonDataKinds.Organization.CONTENT_ITEM_TYPE + "' OR "
                        + ContactsContract.Data.MIMETYPE + "='" + ContactsContract.CommonDataKinds.Email.CONTENT_ITEM_TYPE + "')",
                new String[]{contactId}, null);

        if (cursor != null && cursor.getCount() > 0) {

            while (cursor.moveToNext()) {
                String displayName = cursor.getString(cursor.getColumnIndex(ContactsContract.Data.DISPLAY_NAME));
                contact.setDisplayName(displayName);
                String rowContactId = cursor.getString(cursor.getColumnIndex(ContactsContract.Data.RAW_CONTACT_ID));
                contact.setRawContactId(rowContactId);
                String lookUpKey = cursor.getString(cursor.getColumnIndex(ContactsContract.Data.LOOKUP_KEY));
                contact.setLookupKey(lookUpKey);

                String mimeType = cursor.getString(cursor.getColumnIndex(ContactsContract.Data.MIMETYPE));
                if (mimeType.equals(ContactsContract.CommonDataKinds.Phone.CONTENT_ITEM_TYPE)) {
                    setPhoneList(cursor, contact);
                } else if (mimeType.equals(ContactsContract.CommonDataKinds.Email.CONTENT_ITEM_TYPE)) {
                    setEmailList(cursor, contact);
                } else if (mimeType.equals(ContactsContract.CommonDataKinds.StructuredName.CONTENT_ITEM_TYPE)) {
                    setStructuredName(cursor, contact);
                } else if (mimeType.equals(ContactsContract.CommonDataKinds.Organization.CONTENT_ITEM_TYPE)) {
                    setOrganization(cursor, contact);
                } else if (mimeType.equals(ContactsContract.CommonDataKinds.StructuredPostal.CONTENT_ITEM_TYPE)) {
                    setAddress(cursor, contact);
                }
            }

            cursor.close();
        }
        return contact;
    }

有关详细信息，请查看以下链接。

ContactHelper.java

我希望它会对你有所帮助。

在联系人ID的帮助下获取联系人的所有详细信息

1 个答案: