我试图从字段中删除重复项(并用空格替换它们),前提是前面的字段是相同的。例如:
示例输入:
France Paris Museum of Fine Arts blabala
France Paris Museum of Fine Arts blajlk
France Paris Yet another museum lqmsjdf
France Paris Museum of National History mlqskjf
France Bordeaux Museum of Fine Arts qsfsqf
France Bordeaux City Hall lmqjflqsk
France Bordeaux City Hall lqkjfqlskjflqskfj
Spain Madrid Museum of Fine Arts lqksjfh
Spain Madrid Museum of Fine Arts qlmfjlqsjf
Spain Barcelona City Hall nvqjvvnqk
Spain Barcelona Museum of Fine Arts lmkqjflqksfj
期望的输出:
France Paris Museum of FineArts blabala
blajlk
Yet another museum lqmsjdf
Museum of National History mlqskjf
Bordeaux Museum of Fine Arts qsfsqf
City Hall lmqjflqsk
lqkjfqlskjflqskfj
Spain Madrid Museum of Fine Arts lqksjfh
qlmfjlqsjf
Barcelona City Hall nvqjvvnqk
Museum of Fine Arts lmkqjflqksfj
提前感谢您提供任何帮助。
答案 0 :(得分:1)
尝试一下:
awk -F '\t' 'BEGIN {OFS=FS} {if ($1 == prev1) $1 = ""; else prev1 = $1; if ($2 == prev2) $2 = ""; else prev2 = $2; if ($3 == prev3) $3 = ""; else prev3 = $3; print}' inputfile
这是一个适用于任意数量字段的较短版本(始终打印最后一个字段):
awk -F '\t' 'BEGIN {OFS=FS} {for (i=1; i<=NF-1;i++) if ($i == prev[i]) $i = ""; else prev[i] = $i; print}' inputfile
输出不会与屏幕使用对齐,但会有正确数量的标签。
输出将如下所示:
field1 TAB field2 TAB field3 TAB field4
TAB TAB TAB field4
TAB TAB field3 TAB field4
TAB field2 TAB field3 TAB field4
etc.
如果您需要对齐列,也可以。
修改强>
此版本允许您指定要进行重复数据删除的字段:
#!/usr/bin/awk -f
BEGIN {
FS="\t"; OFS=FS
deduplist=ARGV[1]
ARGV[1]=""
split(deduplist,tmp," ")
for (i in tmp) dedup[tmp[i]]=1
}
{
for (i=1; i<=NF;i++)
if (i in dedup) {
if ($i == prev[i])
$i = ""
else
prev[i] = $i
}
# prevent printing lines that are completely blank because
# it's an exact duplicate of the preceding line and all fields
# are being deduplicated
if ($0 !~ /^[[:blank:]]*$/)
print
}
运行如下:./script.awk "2 3" inputfile
重复删除第2和第3个字段。
答案 1 :(得分:0)
试试这个Perl one-liner:
perl -F"\t" -nae '@O=@F;if(!$x){$x=1}else{for($i=0;$i<=$#S;$i++){$F[$i]=""if($S[$i] eq "" || $S[$i] eq $F[$i])}};print join "\t",@F;@S=@O;'
我假设这些字段是制表符分隔的。