我想确保在按下提交按钮以停止应用程序崩溃之前字段不为空。
这是我的代码
package com.alrabei.edcalactivity;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.text.TextUtils;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
import android.widget.Toast;
public class edcalactivity extends AppCompatActivity {
EditText firstNumber;
EditText secondNumber;
EditText thirdnum;
EditText forthnum;
TextView showresult;
Button buadd1;
double num1,num2,num3,num4,sum1,sum2,sum3,TotalBuy;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.edcal_activity);
firstNumber = (EditText)findViewById(R.id.s1);
secondNumber = (EditText)findViewById(R.id.p1);
thirdnum = (EditText)findViewById(R.id.s2);
forthnum = (EditText)findViewById(R.id.p2);
showresult = (TextView)findViewById(R.id.result);
buadd1 = (Button)findViewById(R.id.bu1);
buadd1.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
num1 = Double.parseDouble(firstNumber.getText().toString());
num2 = Double.parseDouble(secondNumber.getText().toString());
num3 = Double.parseDouble(thirdnum.getText().toString());
num4 = Double.parseDouble(forthnum.getText().toString());
if((firstNumber.getText().length()>0) && (secondNumber.getText().length()>0) && (thirdnum.getText().length()>0) && (forthnum.getText().length()>0))
{
sum1 = num1 + num3;
TotalBuy = (num1 * num2) + (num3 * num4);
// sum2 = num2 + num4;
// sum3 = sum2 / sum1;
sum3 = TotalBuy / sum1;
showresult.setText(Double.toString(sum3));
}
else{
showresult.setText("Error");
}
}
});
}
}

这是xml文件
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:gravity="center"
android:orientation="vertical"
tools:context="com.alrabei.edcalactivity">
<LinearLayout
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:gravity="center"
android:orientation="vertical">
<TextView
android:id="@+id/textView5"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:text="العدد السابق" />
<EditText
android:id="@+id/s1"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:ems="10"
android:inputType="number" />
<TextView
android:id="@+id/textView9"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:text="السعر:" />
<EditText
android:id="@+id/p1"
android:layout_width="171dp"
android:layout_height="wrap_content"
android:ems="10"
android:inputType="number|numberDecimal" />
</LinearLayout>
<LinearLayout
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:gravity="center"
android:orientation="vertical">
<TextView
android:id="@+id/textView8"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:text="الجديد" />
<EditText
android:id="@+id/s2"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:ems="10"
android:inputType="number" />
<TextView
android:id="@+id/textView10"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:text="القيمة:" />
<EditText
android:id="@+id/p2"
android:layout_width="173dp"
android:layout_height="wrap_content"
android:ems="10"
android:inputType="number|numberDecimal" />
</LinearLayout>
<Button
android:id="@+id/bu1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Button" />
<TextView
android:id="@+id/result"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="TextView"
android:maxLength="5"
/>
</LinearLayout>
&#13;
我做了一个if语句,以确保用户在edittext中输入一个数字,但它不起作用..你能帮我解决代码有什么问题吗?
答案 0 :(得分:0)
解析数字后进行检查。这样Double.parseDouble()
在检查空字符串之前就已经尝试访问空字符串了。
您需要围绕onClick()
函数的整个内容包装if语句。
答案 1 :(得分:0)
首先检查EditView是否为空:
if(!firstNumber.getText().toString().trim().equals("")){
//To Do
num1 = Double.parseDouble(firstNumber.getText().toString());
}