Question

我有一个包含以下列的表：

ID

预定日期

状态

目标日期

我需要为每个ID提取与“最短约会日期”相对应的“状态”。如果没有，那么我需要提取与该ID的最小“目标日期”相对应的状态。样本数据：

ID  | Scheduled_Date    | Status |  Target_Date
1      12/11/2017        Completed  12/11/2017
1      12/12/2017        Completed  12/12/2017
2      12/13/2017        Completed  12/13/2017
3      12/14/2017        Pending    12/14/2017
3      12/15/2017        Pending    12/15/2017
4                        Confirmed  12/18/2017
4                        Confirmed  12/19/2017
5      12/14/2017        Completed  12/14/2017
5      12/15/2017        Pending    12/15/2017

请您更正我想写的代码吗？

SELECT ID, 
    CASE WHEN ID IS NOT NULL THEN 
        CASE WHEN MIN(SCHEDULED_DATE) IS NOT NULL 
        THEN STATUS 
        ELSE
        END         
        CASE WHEN MIN(TARGET_DATE) IS NOT NULL 
        THEN STATUS
        ELSE ''
        END
FROM FIRST_STATUS

Answer 1

尝试此查询。

SELECT id,
       status
FROM yourtable t
WHERE COALESCE (Scheduled_Date,
                Target_Date) IN
    (SELECT MIN(COALESCE (Scheduled_Date,Target_Date))
     FROM yourtable i
     WHERE i.ID = t.id
     GROUP BY i.ID);

<强> DEMO

Answer 2

使用select id, status from ( select id, status, row_number() over(partition by id, order by nvl(Scheduled_Date,Target_Date)) rn from yourtable t )s where rn=1 ;分析函数：

{{1}}

HIVE平台的案例陈述

2 个答案: