Question

我有这个问题：

SELECT * FROM (
SELECT DISTINCT on (i.empleado) i.id as id,i.dia as dia,e.id as empleadoId,pe.nombre as personaNombre,pe.apellido1 as personaApellido1,pe.apellido2 personaApellido2 FROM rrhh.imputacion as i 
INNER JOIN rrhh.empleado as e ON e.id = i.empleado 
JOIN commons.persona AS pe ON e.persona_comun = pe.id 
INNER JOIN rrhh.parte__imputaciones as pi ON pi.imputacion = i.id 
INNER JOIN rrhh.parte as p ON pi.parte = p.id 
WHERE p.borrador = false  AND e.fecha_fin_contrato IS NULL AND e.security_domain_id = 2  and e.id 
NOT IN(
SELECT DISTINCT on (i.empleado) i.empleado FROM rrhh.imputacion as i 
 INNER JOIN rrhh.empleado as e ON e.id = i.empleado 
 JOIN commons.persona AS pe ON e.persona_comun = pe.id 
 INNER JOIN rrhh.parte__imputaciones as pi ON pi.imputacion = i.id 
 INNER JOIN rrhh.parte as p ON pi.parte = p.id 
 WHERE i.dia >= '2017-12-04' AND i.dia <= '2017-12-10' and p.borrador = false  AND e.fecha_fin_contrato IS NULL AND e.security_domain_id = 2 
 ORDER  BY i.empleado, i.dia DESC,i.id
)
ORDER  BY i.empleado, i.dia DESC,i.id)
t
ORDER BY t.dia DESC

我需要在“NOT IN”中添加以下查询，并带有OR：

SELECT DISTINCT on (a.empleado) a.empleado FROM rrhh.ausencia as a 
 INNER JOIN rrhh.empleado as e ON e.id = a.empleado 
 JOIN commons.persona AS pe ON e.persona_comun = pe.id 
 INNER JOIN rrhh.parte__imputaciones as pi ON pi.imputacion = a.id 
 INNER JOIN rrhh.parte as p ON pi.parte = p.id 
 WHERE a.dia >= '2017-12-04' AND a.dia <= '2017-12-11' and p.borrador = false  AND e.fecha_fin_contrato IS NULL AND e.security_domain_id = 2 
 ORDER  BY a.empleado, a.dia DESC,a.id

应该有类似于我放下的东西，但这不起作用，因为我不知道语法，我尝试了OR和UNION，但在这两种情况下我都收到错误：

SELECT * FROM (
SELECT DISTINCT on (i.empleado) i.id as id,i.dia as dia,e.id as empleadoId,pe.nombre as personaNombre,pe.apellido1 as personaApellido1,pe.apellido2 personaApellido2 FROM rrhh.imputacion as i 
INNER JOIN rrhh.empleado as e ON e.id = i.empleado 
JOIN commons.persona AS pe ON e.persona_comun = pe.id 
INNER JOIN rrhh.parte__imputaciones as pi ON pi.imputacion = i.id 
INNER JOIN rrhh.parte as p ON pi.parte = p.id 
WHERE p.borrador = false  AND e.fecha_fin_contrato IS NULL AND e.security_domain_id = 2  and e.id 
NOT IN(
SELECT DISTINCT on (i.empleado) i.empleado FROM rrhh.imputacion as i 
INNER JOIN rrhh.empleado as e ON e.id = i.empleado 
JOIN commons.persona AS pe ON e.persona_comun = pe.id 
INNER JOIN rrhh.parte__imputaciones as pi ON pi.imputacion = i.id 
INNER JOIN rrhh.parte as p ON pi.parte = p.id 
WHERE i.dia >= '2017-12-04' AND i.dia <= '2017-12-10' and p.borrador = false  AND e.fecha_fin_contrato IS NULL AND e.security_domain_id = 2 
ORDER  BY i.empleado, i.dia DESC,i.id
OR -- UNION   
SELECT DISTINCT on (a.empleado) a.empleado FROM rrhh.ausencia as a 
INNER JOIN rrhh.empleado as e ON e.id = a.empleado 
JOIN commons.persona AS pe ON e.persona_comun = pe.id 
INNER JOIN rrhh.parte__imputaciones as pi ON pi.imputacion = a.id 
INNER JOIN rrhh.parte as p ON pi.parte = p.id 
WHERE a.dia >= '2017-12-04' AND a.dia <= '2017-12-11' and p.borrador = false  AND e.fecha_fin_contrato IS NULL AND e.security_domain_id = 2 
ORDER  BY a.empleado, a.dia DESC,a.id   
 )
ORDER  BY i.empleado, i.dia DESC,i.id)
t
ORDER BY t.dia DESC

Answer 1

I need to add the query below in the "NOT IN", with an OR:

我不知道你的意思是＆＃34;用OR＆＃34;。如果您的意思是e.id应该是NOT IN第一个子查询或不在第二个子查询中，您可以这样做：

...
AND (
    e.id NOT IN (
        SELECT DISTINCT ...
    ) OR (
    e.id NOT IN (
        SELECT DISTINCT ...
    )
)

如果你不希望它在任何一个（因此尝试联盟），只需将OR改为AND。

虽然我怀疑此查询的查询计划会很差。当有很多结果时，IN和NOT IN是低效的。

此外代码也很奇怪。你的大多数联接都是明确的INNER JOIN，但有几个只是说JOIN。但是默认情况下JOIN是INNER JOIN。那么为什么有些线条明确而其他线条隐含？为什么整个代码的样式不同？例如，AS vs as，从一行到下一行...

双重选择进入NOT IN

1 个答案: