Question

我有以下数据，包含2个不同的TBL_ID - 337448和8612

"TBL_ID","PARAM_KEY","PARAM_VALUE"
 337448,"comment","CHANGE DUE"
 337448,"transient_lastDdlTime","1505760292"
 8612,"COLUMN_STATS_ACCURATE","true"
 8612,"numFiles","1"
 8612,"numRows","5294"
 8612,"rawDataSize","-1"
 8612,"totalSize","113217"
 8612,"transient_lastDdlTime","1452191300"

我需要查询不包含“numRows”的所有TBL_ID 我尝试过：

SELECT * FROM TABLE_PARAMS 
WHERE PARAM_KEY NOT IN ('numRows')

结果：

"TBL_ID","PARAM_KEY","PARAM_VALUE"
 337448,"comment","CHANGE DUE"
 337448,"transient_lastDdlTime","1505760292"
 8612,"COLUMN_STATS_ACCURATE","true"
 8612,"numFiles","1"
 8612,"rawDataSize","-1"
 8612,"totalSize","113217"
 8612,"transient_lastDdlTime","1452191300"

它确实用numRows删除了列但我需要删除整个TBL_ID（8612）

Answer 1

NOT IN ('numRows')

基本上是一个不等于

<> 'numRows'

通常，使用带有多个值的NOT IN来简化编写一大堆

mycol <> 'a' and mycol <> 'b' and mycol <> 'c'

然后写下

mycol NOT IN ('a', 'b', 'c')

或使用像

这样的子查询

mycol NOT IN (SELECT badcols FROM table)

您的使用似乎是NOT EXISTS比NOT IN更有用的情况。

SELECT * 
FROM TABLE_PARAMS t1
WHERE NOT EXISTS (SELECT * FROM TABLE_PARAMS t2 WHERE t2.tbl_id = t1.tbl_id and t2.param_key<>'numFiles')

或者你可以使用像

这样的外连接做同样的事情

SELECT t1.*
FROM TABLE_PARAMS t1 left outer join TABLE_PARAMS t2
  on t1.tbl_id = t2.tbl_id and t2.param_key='numFiles'
WHERE t2.tbl_id IS NULL

Answer 2

你的问题有点含糊不清。 IN运算符用于从结果集中查找数据。例如，2 IN {2,3,4}。

SELECT TBL_ID FROM  TABLE_PARAMS
WHERE PRAMAR_KEY='numRows'

如果您尝试不显示与numRows关联的任何ID，则必须首先获取要过滤的ID，并将用户NOT EQUALS设置为。例如，如果您尝试从集合中删除8612，因为它是Param_Key ='numRows'和的ID，如果您正在尝试在操作员中使用，那么

SELECT * FROM TABLE_PARAMS
WHERE TBL_ID NOT IN (SELECT TBL_ID FROM TABLE_PARAMS WHERE PARAM_KEY='numRows')

MySQL NOT IN运算符

2 个答案: