我正在做一个简单的GroupBy获取First元素,但我想修改每个结果的一个属性。
class M
{
public string Name {get; set;}
public int NOfPeopleWithTheSameName {get; set;}
public string P1 {get; set;}
public string P2 {get; set;}
public string P3 {get; set;}
public string P4 {get; set;}
public string P5 {get; set;}
}
List<M> myList = GetMyList();
var l2 = myList
.GroupBy(m => m.Name)
.Select(group => new M { Name = group.Key, NOfPeopleWithTheSameName = group.Count() });
这很简单,但如果类有很多属性(因为每个属性值都应该复制到新属性),这种方式不是最好的方法吗?我应该逐个复制它们。
我想简单地取元素并更改属性NOfPeopleWithTheSameName
答案 0 :(得分:2)
您不需要创建新的M
,您可以返回现有的var l2 = myList
.GroupBy(m => m.Name)
.Select(group =>
{
var m = group.First();
m.NOfPeopleWithTheSameName = group.Count();
return m;
});
,例如:
public class ModelCount<T>
{
public T Model { get; set; }
public int Count { get; set; }
}
但是,如果你打算为你的模型添加一个属性,我建议改为使用另一个包装初始模型和计数的类 - 不要污染你的模型。例如,您可以使用这样的通用包装类:
var l2 = myList
.GroupBy(m => m.Name)
.Select(group => new ModelCount<M>
{
Model = group.First(),
Count = group.Count()
});
现在这样组:
@Component({
selector: 'app-transmission-history'
})
export class TransmissionHistoryComponent implements OnInit {
@Input() theRecord: Record = null;
constructor(private _transmissionHistoryService: TransmissionHistoryService) { }
}
答案 1 :(得分:1)
是的,你可以 ......
class Test
{
public string Name { get; set; }
public int Number { get; set; }
}
var tests = new List<Test> { /* ... your data here ... */ };
var modifiedTests = tests.Select(test => { test.Name = "MODIFIED"; return test; });
// this actually executes above query and modifies your original items in the list:
var modifiedMaterialized = modifiedTests.ToList();
但你真的,真的(!)不应该!
LinQ是语言集成查询。有副作用的查询是邪恶的。胡子扭曲邪恶。不管怎样,你会为自己省下很多痛苦。
我认为你想要的不仅仅是LinQ,而是常规循环:
class M
{
public string Name {get; set;}
public int NOfPeopleWithTheSameName {get; set;}
public string P1 {get; set;}
public string P2 {get; set;}
public string P3 {get; set;}
public string P4 {get; set;}
public string P5 {get; set;}
}
List<M> myList = GetMyList();
var groups = myList.GroupBy(m => m.Name).ToList();
foreach(var group in groups)
{
foreach(var member in group)
{
member.NOfPeopleWithTheSameName = group.Count();
}
}