Question

我需要用户输入成绩（A，B，C ......）然后我可以使用它转换为4,3,2,1,0并找到GPA

def grade(ge):
    grade = ['A','B','C', 'D', 'F']
    getitem(grade);
    if grade == 'A': grade = 4;
    elif grade == 'B': grade = 3;
    elif grade == 'C': grade = 2;
    elif grade == 'D': grade = 1;
    elif grade == 'F': grade = 0;
    else:
        print 'error' 
    total=0
    for a in ge:
        total=grade+total;
    GPA=total/8;
    print 'GPA = ', GPA

Answer 1

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所需要的只是def list_of_grades(lst): grades = ['A','B','C','D','F'] scores = [4,3,2,1,0] if any(lst) not in grades: return "Cannot convert" lst_grades = [scores[grades.index(l)] for l in lst] return sum(lst_grades)/len(lst_grades)是一个等级列表，例如lst

Answer 2

def convert_grades(grades):
    total=0
    for g in grades:
        if   g == 'A': score = 4
        elif g == 'B': score = 3
        elif g == 'C': score = 2
        elif g == 'D': score = 1
        elif g == 'F': score = 0
        else:
            print("Can't convert grade '%s'") % (g)
            break
        total+=score
    GPA=total/len(grades)

    return(GPA)

lowgrades = ['C','D','A', 'C', 'B']
highgrades = ['A','A','A', 'B', 'A']

print("GPA: %s") % (convert_grades(lowgrades))
print("GPA: %s") % (convert_grades(highgrades))

Answer 3

虽然@fugu的答案看起来最接近你想要的，你也可以使用字典或通过使用单个列表摆脱if..elif。此外，如果您将8更改为len(ge)，则此函数将适用于任何长度的输入。

def get_grade(ge):
    #using a dictionary
    grade_values={'A':4,'B':3,'C':2, 'D':1, 'F':0}

    total=0
    for a in ge:
      if a in grade_values:
        total=grade_values[a]+total;
      else:
        print('error')
        break # or remove this line to keep calculating
    GPA=total/len(ge)
    print('GPA = '+str(GPA))

    # or use a single list, this list contains the valid input values in order
    grade_def = ['A','B','C', 'D', 'F']
    total=0
    for a in ge:
      try:
        # grade_def.index(a) returns the location or an error if not found
        total=len(grade_def)-1-grade_def.index(a)+total;
      except:
        print('error')
        break
    GPA=total/len(ge)
    print( 'GPA = '+str(GPA)) #same output as the first example

get_grade(['A','C','C','B','A','A','D','A'])
get_grade(['A','C','C','B','A','A','D','Q']) # will print an error

获取python中的单词列表

3 个答案: