Ansible,list对象没有属性

时间:2017-12-15 11:58:00

标签: ansible ansible-2.x

我正在使用Ansible 2.3.0.0并且我在Ansible 2.4.0.0中进行了测试,获得了相同的结果。我的问题很简单,但我看不出问题。

我在Ansible中定义了一个对象列表,如下所示:

  vars:
     password_text_to_encrypt:
          - { line: "{{truststore_pass }}" , regexp: '\${TRUSTSTORE_PASS}*'}
          - { line: "{{ keystore_pass }}" , regexp: '\${KEYSTORE_PASS}*'}
          - { line: "{{ gp_pass }}" , regexp: '\${GP_PASS}*'}
          - { line: "{{ datasource_password }}" , regexp: '\${DATASOURCE_PASS}*'}
          - { line: "{{ server_password }}" , regexp: '\${SERVER_PASSWORD}*'}
          - { line: "{{ sftp_password }}" , regexp: '\${SFTP_PASSWORD}*'}
          - { line: "{{ db_userpassword }}" , regexp: '\${DB_PASSWORD}*'}
     roles:
       - basic_role

My Basic_role只打印项目,我想获取每行的内容:

---

- name: "print password"
  debug: 
    msg: "The content of the line is: {{ item.line}}"
  with_nested:
    - "{{password_text_to_encrypt}}"

但我获得的结果是:

FAILED! => {"failed": true, "msg": "the field 'args' has an invalid value, which appears to include a variable that is undefined. The error was: 'list object' has no attribute 'line'\n\nThe error appears to have been in.....

如果我将item.line更改为item,则可以正常显示:

ok: [localhost] => (item=[u'regexp', u'line']) => {
    "item": [
        "regexp",
        "line"
    ],
    "msg": "The content of the line is: [u'regexp', u'line']"
}
.
.
.

总而言之,Ansible不考虑line o regexp的内容。我一直在做测试,用于init line和regexp的变量不是空的。

2 个答案:

答案 0 :(得分:1)

使用with_items代替with_nested

答案 1 :(得分:-1)

我认为您需要loops and includes,因为您正在获得预期的扁平列表(根据文档)。