使用单一方法从多个输入字段计算年龄

时间:2017-12-15 10:03:29

标签: javascript jquery angularjs

这是我计算年龄的代码。我在ng-change中对多个输入使用相同的方法。
但是我可以使用单一方法仅对一个输入字段绑定年龄。
为什么要和#39; t我使用单一方法根据模型名称绑定多个输入的结果数据?



var app = angular.module('myApp', [])
app.controller('myController', function($scope) {
   
     $scope.calculateAge = function (fieldName,value) {debugger
        var birthDay =value;
        var DOB = new Date(birthDay);
        var today = new Date();
        var age = today.getTime() - DOB.getTime();
        age = Math.floor(age / (1000 * 60 * 60 * 24 * 365.25));
       
        fieldName=age;
        //$scope.data1.age=age;
    }
})

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="myApp" ng-controller="myController" ng-init="init()">
<div>
    <input type="date" ng-model="data1.dob" ng-change="calculateAge(data1.age,data1.dob)"/>
    <input type="text" ng-model="data1.age"/>
</div>
<div>
    <input type="date" ng-model="data2.dob" ng-change="calculateAge(data2.age,data2.dob)"/>
    <input type="text" ng-model="data2.age"/>
    </div>
    
</div>
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我知道我可以通过传递输入ID来做。但我正在尝试它的型号名称。

2 个答案:

答案 0 :(得分:1)

试试这个:$scope[fieldName] =age;

var app = angular.module('myApp', [])
app.controller('myController', function($scope) {

     $scope.calculateAge = function (fieldName,value) {debugger
        var birthDay =value;
        var DOB = new Date(birthDay);
        var today = new Date();
        var age = today.getTime() - DOB.getTime();
        age = Math.floor(age / (1000 * 60 * 60 * 24 * 365.25));

        //fieldName=age;
        $scope[fieldName] =age;// $scope[value] is eq. to $scope.data2.age
    }
})

答案 1 :(得分:1)

您必须在方法中传递data的引用并修改它。

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var app = angular.module('myApp', [])
app.controller('myController', function($scope) {
   
     $scope.calculateAge = function (data) {debugger
        var birthDay = data.dob;
        var DOB = new Date(birthDay);
        var today = new Date();
        var age = today.getTime() - DOB.getTime();
        age = Math.floor(age / (1000 * 60 * 60 * 24 * 365.25));
        data.age = age;
    }
})
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<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="myApp" ng-controller="myController" ng-init="init()">
<div>
    <input type="date" ng-model="data1.dob" ng-change="calculateAge(data1)"/>
    <input type="text" ng-model="data1.age"/>
</div>
<div>
    <input type="date" ng-model="data2.dob" ng-change="calculateAge(data2)"/>
    <input type="text" ng-model="data2.age"/>
    </div>
    
</div>
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